The frequency of the periodic function is given by: 0.0796.
<h3>What are the period and the frequency of a function?</h3>
- The period of a function is given by the <u>distance between it's repetitions</u>.
- The frequency of a function is found <u>dividing one by the period</u>.
From the graph, we have that the period is of 4pi hours, hence the frequency is:
f = 1/4pi = 0.0796.
More can be learned about periodic functions at brainly.com/question/27894133
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Answer:
Step-by-step explanation:
Give the data
198 sq.yd × 8 sq ft ×7
Note that we have two unit of measurement which are yd and ft and 7 is just a constant
So we need to convert them,
Then, 1 yd = 3ft
Also notice that they are square.
Then square both sides of the comparison
(1 yd)² = (3 ft)²
1 sq.yd = 9 sq.ft
Then, back to our question,
198 sq.yd × 8 sq ft ×7
Let covert to ft
198 sq.yd× (9 sq.ft/1 sq.yd) ×8 sq.ft×7
sq.yd cancels out
99,792 sq.ft × sq.ft
99,792 ft⁴
Let convert to yd
198 sq.yd × 8 sq ft ×7
198 sq.yd×8 sq.ft (1 sq.yd / 9sq.ft )×7
1,232 sq.yd × sq.yd
1,232 yd⁴
2x + 3y = 12
I am going to put this in y = mx + b form, where m is ur slope and b is ur y intercept.
2x + 3y = 12
3y = -2x + 12
y = -2/3x + 4......slope is -2/3 and y int is (0,4)
x int can be found by subbing in 0 for y and solving for x
2x + 3y = 12
2x + 3(0) = 12
2x = 12
x = 6.....so x int is (6,0)
start at y int (0,4).....and since the slope is -2/3, come down 2 spaces, and to the right 3 spaces, then down 2 spaces, to the right 3 spaces....keep doing that and u should cross the x axis at (6,0)
-2 becuase the b take our themselfvss
