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shtirl [24]
3 years ago
15

So Can Someone Help Me Please Asap!!!!!!!!!!!!!!!!!!!!!!!

Physics
1 answer:
eimsori [14]3 years ago
3 0

Answer:

The Laws of Badminton

A match consists of the best of 3 games of 21 points.

Every time there is a serve – there is a point scored.

The side winning a rally adds a point to its score.

At 20 all, the side which gains a 2 point lead first, wins that game.

At 29 all, the side scoring the 30th point, wins that game.

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How do the forces acting on a boat compare to the force acting on a plane ?
erica [24]

Answer:

on there boat there will two main forces act 1,upthrust which comes from water and air and other side on the plane air and gravity.

Explanation:

7 0
3 years ago
Read 2 more answers
It takes 50 seconds for Tyler to do 450 Joules of work. How much power did Tyler use?​
Bogdan [553]
Power=work/time
So,
Power =450/50=9watts
8 0
3 years ago
Read 2 more answers
The aluminum wire in a high-voltage transmission line is 2.7 cm in diameter. It is designed to carry a current of 1100 A. What i
marissa [1.9K]

Answer:

1660 V

Explanation:

Resistance should be determined and then voltage drop across the power line can be determined.

R = ρ L /A  

Here ρ = Resistivity of aluminum = 2.7\times 10^{-8}\Omega m

L = length = 32 km = 32,000 m

Area of cross section = A = π r² = π (0.027/2)² = 0.00057255 m²

Resistance = R =

(2.7\times 10^{-8}\Omega m (32,000)/(0.00057255) = 1.5090 Ohms.

Voltage drop = V = I R = (1100)(1.5090) = 1659.9 V.

(If resistivity value is different, then the resistance will be different and hence final answer for voltage will also vary ).

4 0
3 years ago
A revolutionary war cannon, with a mass of 2090 kg, fires a 16.7 kg ball horizontally. The cannonball has a speed of 113 m/s aft
OLEGan [10]

Answer:

0.90291 m/s

0.45055 m/s

Explanation:

m_1 = Mass of canon = 2090 kg

m_2 = Mass of ball = 16.7 kg

v_1 = Velocity of canon

v_2 = Velocity of ball = 113 m/s

In this system the momentum is conserved

m_1v_1=m_2v_2\\\Rightarrow v_1=\dfrac{16.7\times 113}{2090}\\\Rightarrow v_1=0.90291\ m/s

The velocity of the cannon is 0.90291 m/s

Applying energy conservation

\dfrac{1}{2}m_1v_1^2+\dfrac{1}{2}m_2v_2^2=\dfrac{1}{2}m_2v^2\\\Rightarrow m_1v_1^2+m_2v_2^2=m_2v^2\\\Rightarrow v_2=\sqrt{\dfrac{m_1v_1^2+m_2v_2^2}{m_2}}\\\Rightarrow v_2=\sqrt{\dfrac{2090\times 0.90291^2+16.7\times 113^2}{16.7}}\\\Rightarrow v_2=113.45055\ m/s

The ball would travel 113.45055-113 = 0.45055 m/s faster

6 0
4 years ago
A negative charge of -6.0x10-6 C exerts an
Ray Of Light [21]

The magnitude of the second charge given that the first is –6×10¯⁶ C and is located 0.05 m away is +3.0×10¯⁶ C

<h3>Coulomb's law equation </h3>

F = Kq₁q₂ / r²

Where

  • F is the force of attraction
  • K is the electrical constant
  • q₁ and q₂ are two point charges
  • r is the distance apart

<h3>How to determine the second charge </h3>
  • Charge 1 (q₁) = –6×10¯⁶ C
  • Electric constant (K) = 9×10⁹ Nm²/C²
  • Distance apart (r) = 0.05 m
  • Force (F) = 65 N
  • Charge 2 (q₂) =?

F = Kq₁q₂ / r²

Cross multiply

Fr² = Kq₁q₂

Divide both side by Kq₁

q₂ = Fr² / Kq₁

q₂ = (65 × 0.05²) / (9×10⁹ × 6×10¯⁶)

q₂ = +3.0×10¯⁶ C (since the force is attractive)

Learn more about Coulomb's law:

brainly.com/question/506926

7 0
2 years ago
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