Answer:
   t = 0.714 s and  x = 5.0 m
Explanation:
This is a projectile throwing exercise, in this case when the skater leaves the bridge he goes with horizontal speed
          vₓ = 7.0 m / s
Let's find the time it takes to get to the river
          y = y₀ + v_{oy} t - ½ g t²
the initial vertical speed is zero and when it reaches the river its height is zero
         0 = y₀ + 0 - ½ g t²
         t =  
         t = ra 2 2.5 / 9.8
         t = 0.714 s
the distance traveled is
        x = vₓ t
        x = 7.0 0.714
        x = 5.0 m
 
        
             
        
        
        
Answer:
x = 1.6 + 1.7 t^2      omitting signs
a) at t = 0     x = 1.6 m
b) V = d x / d t = 3.4 t
at t = 0     V = 0
c) A = d^2 x / d t^2 = 3.4     (at t = 0  A = 3.4 m/s^2)
d)  x = 1.6 + 1.7 * (4.4)^2 = 34.5    (position at 4.4 sec = 34.5 m)
 
        
             
        
        
        
Answer:
a luminous ball of plasma