*

If a magnet could swing freely, what would happen to its north-seeking pole?

maksim [4K]

You clearly identified the pole you're talking about as the
"north-seeking" pole. Assuming your integrity and sincerity,
we would then naturally expect that pole to seek north, and
point to Earth's north magnetic pole.

I'm confident in this answer also because I have several of
these devices hanging from the ceiling of my office, and I can
attest to the fact that on most clear days, they do in fact point
toward Earth's north magnetic pole.

8 0

4 years ago

student built a simple heat engine that could lift masses. If the heat engine takes in 300 J of heat and loses 50 J to the envir

k0ka [10]

Answer:

So it will lift the mass by h = 17 m

Explanation:

As per energy conservation we know that

$Q_1 = W + Q_2$

here we know that

$Q_1 = 300 J$

$Q_2 = 50 J$

now we have

$W = 300 - 50$

$W = 250 J$

so work done by the engine is 250 J

now we have

$W = mgh$

$250 = 1.5 \times 9.81 \times h$

$h = 17 m$

4 0

3 years ago

An 8.7 g bullet is accelerated in a rifle barrel 105 cm long to a speed of 465 m/s. Use the work-energy theorem to find the aver

Viktor [21]

Answer:896 N

Explanation:

Given

mass of bullet $m=8.7 gm$

Length of barrel $d=105 cm=1.05 m$

final velocity $v=465 m/s$

initial velocity $u=0 m/s$

Work done by all the forces is equal to change in kinetic Energy

$F\cdot d=\frac{1}{2}\times mv^2-0$

$F_{avg}\times 1.05=\frac{1}{2}\times 8.7\times 10^{-3}\times 465^2$

$F_{avg}=\frac{0.5\times 8.7\times 10^{-3}\times 465^2}{1.05}$

$F_{avg}=895.789 Na\pprox 896 N$

6 0

4 years ago

3) While flying horizontally in an airplane, you notice that a string dangling from the overhead

SOVA2 [1]

Answer:

A

Explanation:

the string would be dangling backwards because you are moving forward it would be putting backward force on the string

7 0

3 years ago

Particles q1, q2, and q3 are in a straight line.

natima [27]

The net force on q2 will be 1.35 N

A force in physics is an effect that has the power to alter an object's motion. A mass-containing object's velocity can vary, or accelerate, as a result of a force. Intuitively, a push or a pull can also be used to describe force. Being a vector quantity, a force has both magnitude and direction.

Given Particles q1, q2, and q3 are in a straight line. Particles q1 = -5.00 x 10-6 C,q2 = +2.50 x 10-6 C, and q3 = -2.50 x 10-6 C. Particles q₁ and q2 are separated by 0.500 m. Particles q2 and q3 are separated by 0.250 m.

We have to find the net force on q2

At first we will find Force due to q1

F = 9 × 10⁹ × 5 × 10⁻⁶ × 2.5 × 10⁻⁶ / 0.5²

F = 450 × 10⁻³

F₁ = 0.45 N (+)

Now we will find Force due to q2

F = 9 × 10⁹ × 5 × 10⁻⁶ × 2.5 × 10⁻⁶ / 0.25²

F = 1800 × 10⁻³

F₂ = 1.8 N (-)

So net force (F) will be

F = F₂ - F₁

F = 1.8 - 0.45

F = 1.35 N

Hence the net force on q2 will be 1.35 N

Learn more about force here:

brainly.com/question/25573309

#SPJ10

8 0

2 years ago