Answer:
I think it is b but I could be wrong
Applying the trigonometry ratios, we have:
a. CD = 63.6
b. CD = 33.8
c. CD = 16.1
d. CD = 15.9
<h3>What are the Trigonometry Ratios?</h3>
The trigonometry ratios are used to find a length or angle in any right triangle. They are:
- SOH, which is sin ∅ = opp/hyp
- CAH, which is cos ∅ = adj/hyp
- TOA, which is tan ∅ = opp/adj
a. ∅ = 32°
hyp = 75
adj = CD
Apply CAH:
cos 32 = CD/75
CD = cos 32 × 75
CD = 63.6
b. ∅ = 56°
opp = 28
hyp = CD
Apply SOH:
sin 56 = 28/CD
CD = 28/sin 56
CD = 33.8
c. ∅ = 43°
opp = 15
adj = CD
Apply TOA:
tan 43 = 15/CD
CD = 15/tan 43
CD = 16.1
d. ∅ = 27°
hyp = 35
opp = CD
Apply SOH:
sin 27 = CD/35
CD = sin 27 × 35
CD = 15.9
Learn more about the trigonometry ratios on:
brainly.com/question/10417664
Answer:
y(t) = c₁ e^(-1/2 t) cos(√3/2 t) + c₂ e^(-1/2 t) sin(√3/2 t) + 1
Step-by-step explanation:
y" + y' + y = 1
This is a second order nonhomogenous differential equation with constant coefficients.
First, find the roots of the complementary solution.
y" + y' + y = 0
r² + r + 1 = 0
r = [ -1 ± √(1² − 4(1)(1)) ] / 2(1)
r = [ -1 ± √(1 − 4) ] / 2
r = -1/2 ± i√3/2
These roots are complex, so the complementary solution is:
y = c₁ e^(-1/2 t) cos(√3/2 t) + c₂ e^(-1/2 t) sin(√3/2 t)
Next, assume the particular solution has the form of the right hand side of the differential equation. In this case, a constant.
y = c
Plug this into the differential equation and use undetermined coefficients to solve:
y" + y' + y = 1
0 + 0 + c = 1
c = 1
So the total solution is:
y(t) = c₁ e^(-1/2 t) cos(√3/2 t) + c₂ e^(-1/2 t) sin(√3/2 t) + 1
To solve for c₁ and c₂, you need to be given initial conditions.
I'm positive the property is commutative property because you only switched the position of the numbers and got the same outcome.
Complete the square by adding the square of half of four to both sides (4)
x^2+y^2-4y+4=4
x^2+(y-2)^2=4
