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3 years ago

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Suppose Team A has a 0.75 probability to win their next game and Team B has a 0.85 probability to win their next game. Assume th

ese events are independent. What is the probability that Team A wins and Team B loses

1 answer:

vovangra [49]3 years ago

8 0

Answer:

B has a higer probability

Step-by-step explanation:

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Gina Wilson unit 3: homework 6: Slope intercept form and standard form HELP

Goshia [24]

Answer:

1.) 2x-y=-7 --> y=2x + 7

2.) 5x+3y=12 --> y= -5/3x + 4

3.) x-y=1 --> y= x- 1

4.) x-3y=-15 --> y=1/3x + 5

5.) 8x-10y=20 --> y=4/5x - 2

6.) 14x+6y=36 --> y=-7/3x+6

Step-by-step explanation:

Hope this helped.

8 0

3 years ago

Winning the jackpot in a particular lottery requires that you select the correct four numbers between 1 and 42 and, in a separa

NARA [144]

Answer:

$\dfrac{1}{3,357,900}$

Step-by-step explanation:

There are

$C^{42}_4=\dfrac{42!}{4!(42-4)!}=\dfrac{42!}{4!\cdot 38!}=\dfrac{38!\cdot 39\cdot 40\cdot 41\cdot 42}{2\cdot 3\cdot 4\cdot 38!}=39\cdot 10\cdot 41\cdot 7=111,930$

different ways to select the four numbers between 1 and 42. Only one of this ways is correct (successful to win).

There are 30 different ways select the single number between 1 and 30. Only one of them is correct.

The probability of winning the jackpot is

$\dfrac{1}{111,930}\cdot \dfrac{1}{30}=\dfrac{1}{3,357,900}$

4 0

3 years ago

Read 2 more answers

Which of the following would be an acceptable first step in simplifying the expression sinx/1-sinx

Paha777 [63]

$\bf \textit{difference of squares}
\\\\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)
\\\\\\
\textit{also recall that }sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)\\\\
-------------------------------$

$\bf \cfrac{sin(x)}{1-sin(x)}\implies \cfrac{sin(x)}{1-sin(x)}\cdot \cfrac{1+sin(x)}{1+sin(x)}\implies \stackrel{first~step}{\cfrac{sin(x)[1+sin(x)]}{[1-sin(x)][1+sin(x)]}}
\\\\\\
\cfrac{sin(x)[1+sin(x)]}{1^2-sin^2(x)}\implies \cfrac{sin(x)[1+sin(x)]}{cos^2(x)}
\\\\\\
\cfrac{sin(x)+sin^2(x)}{cos^2(x)}\implies \cfrac{sin(x)}{cos^2(x)}+ \cfrac{sin^2(x)}{cos^2(x)}
\\\\\\
\cfrac{sin(x)}{cos(x)}\cdot \cfrac{1}{cos(x)}+\cfrac{sin^2(x)}{cos^2(x)}\implies tan(x)sec(x)+tan^2(x)
\\\\\\
tan(x)[sec(x)+tan(x)]$

8 0

3 years ago

Read 2 more answers

Which describes how to find the solution 5k >22

inysia [295]

Answer:

<h2>k > 4.4</h2>

Step-by-step explanation:

$5k>22\qquad\text{divide both sides by 5}\\\\\dfrac{5k}{5}>\dfrac{22}{5}\\\\k>4\dfrac{2}{5}\to k>4.4\to k\in(4.4,\ \infty)$

8 0

3 years ago

Dr. Betz, a vet, is running a free rabies clinic. He estimates that it will take him 12 minutes for each animal he treats. Dr. B

Olin [163]

Answer:

equation: y = 12x

Dr. Betz worked for 8 hours.

Step-by-step explanation:

To write the equation we'll use the form y = mx, where y represents the amount of time the Doctor worked, m is the amount of minutes it takes to treat each animal, and x is how many animals have been treated. We know the value of m is 12, so let's put that into the equation:

y = 12x

Now we have our equation. We can use it to see how long Dr. Betz worked. He treated a total of 40 animals - 20 including the shaggy dog, and 20 after the shaggy dog. let's replace x with 40:

y = 12(40)

Now solve:

y = 480

Dr. Betz worked for 480 minutes. There are 60 minutes in an hour. Divide 480 by 60 to find out how many hours Dr. Betz worked for:

480/60 = 8

Dr. Betz worked for 8 hours.

7 0

3 years ago