A radar antenna, making one revolution every 5 seconds, is located on a ship that is 6 km from a straight shoreline. How fast is
the radar beam moving along the shoreline when the beam makes an angle of 45◦ with the shore?
1 answer:
Answer:
The figure below is showing the situation:
Figure
Now let the point is at a distance x from the shoreline where it is making the angle of 45 degrees.
So we have:
x
=
6
tan
θ
Now we have:
d
θ
d
t
=
2
π
5
So we have to find the velocity that is given by:
d
x
d
t
=
d
d
θ
(
6
tan
θ
)
=
6
sec
2
(
θ
)
d
θ
d
t
=>
d
x
d
t
=
6
sec
2
(
π
4
)
2
π
5
is the required velocity
Step-by-step explanation:
does that answer your question
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20x(less than or equal to sign) 300
divide both sides by 20 and you get x is less than or equal to 15
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Explanation:
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5 x 16=80
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Answer:
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Step-by-step explanation:
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