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3 years ago

Write two numbers, neither of which is 28, whose LCM is 28.

Mathematics

1 answer:

SOVA2 [1]3 years ago

5 0

Answer: 4 and 7

Step-by-step explanation:

The LCM (least common multiple) of two numbers is the smallest number (different from zero) that is a multiple of both.

So, we need to find 2 numbers different from 28 that have 28 as a multiple and it has to be the least one, so this numbers must be smaller than 28.

If we look into all the numbers smaller than 28 that have 28 as a multiple we find: 2, 4, 7 and 14

The only 2 that have the LCM 28 are 4 and 7.

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3 years ago

The tables represent two linear functions in a system,

Alenkasestr [34]

Answer:

Step-by-step explanation:

The slope-intercept form of an equation of a line:

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$m=\dfrac{y_2-y_1}{x_2-x_1}$

First table:

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Second table:

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We have the system of equations:

$\left\{\begin{array}{ccc}y=-4x+10&(1)\\y=-3x+2&(2)\end{array}\right\\\\\text{Put (1) to (2):}\\\\-4x+10=-3x+2\qquad\text{subtract 10 from both sides}\\-4x=-3x-8\qquad\text{add 3x to both sides}\\-x=-8\qquad\text{change the signs}\\x=8\\\\\text{Put the value of x to (2):}\\\\y=-3(8)+2\\y=-24+2\\y=-22$

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3 years ago

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max2010maxim [7]

Answer:

C, 5/2

Step-by-step explanation:

3 I2x -1I + 4 = 16

Isolate absolute value:

3 I2x -1I + 4 - 4 = 16 - 4

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(3 I2x -1I) / 3 = 12 / 3

I2x -1I= 4

Since the question is only asking for the positive, all you need to solve for is the +4. Solve for x

2x -1 = 4

2x -1 + 1 = 4 +1

2x = 5

2x / 2 = 5 / 2

x = 5/2 or C

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3 years ago

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WARRIOR [948]

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