Answer:
The probability that the average score of the 49 golfers exceeded 62 is 0.3897
Step-by-step explanation:
The average score of all golfers for a particular course has a mean of 61 and a standard deviation of 3.5


We are supposed to find he probability that the average score of the 49 golfers exceeded 62.
Formula : 


Refer the z table for p value
p value = 0.6103
P(x>62)=1-P(x<62)=1-0.6103=0.3897
Hence the probability that the average score of the 49 golfers exceeded 62 is 0.3897
Bob the numerator and denominator are divisible by 3 so the simplified fraction would be 9/17
18.47Answer:
Step-by-step explanation:
The answer is C.(-2,3)<span />
Answer:
5a^4+a^2b−6b^2
Step-by-step explanation:
1. Use the FOIL method: (a+b)(c+d)=ac+ad+bc+bd.
5a^4+6a^2b−5ba^2−6b^2
2. Collect like terms.
5a^4+(6a^2b−5a^2b)−6b^2
3. Simplify.
5a^4+a^2b−6b^2