Answer: The mean is greater than the median
when finding the mean then add the numbers then divide them by the amount of numbers there are when finding the median find the middle number and if there is no middle number divide the 2 and that should be your mean
For easier notation lets use: Nn=x and Nd=y
x+y=22
5x+10y=135
Multiply the first equation by 5 to get
5x+5y=110
Now you can eliminate x by subtracting the first equation from the second
5x+10y-5x-5y=135-110
5y=25
y=5
x=17
3x-22+x=180
4x-22=180
4x=202
X=202/4
X=50.5
3(50.5)-22=129.5
5-.5+129.5=180
The problem you have written
![\sqrt[5]{x^{10}}/2](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%5E%7B10%7D%7D%2F2)
simplifies to

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If you intend
![\sqrt[5]{x^{10}/2}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%5E%7B10%7D%2F2%7D)
then you can multiply by the appropriate fraction to get your first answer choice.
![\displaystyle\sqrt[5]{\frac{x^{10}}{2}}=\frac{\sqrt[5]{x^{10}}}{\sqrt[5]{2}}\cdot\frac{\sqrt[5]{2^4}}{\sqrt[5]{2^4}}\\\\=\frac{x^{2}\sqrt[5]{16}}{\sqrt[5]{2^{5}}}=\bf{\frac{x^{2}\sqrt[5]{16}}{2}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Csqrt%5B5%5D%7B%5Cfrac%7Bx%5E%7B10%7D%7D%7B2%7D%7D%3D%5Cfrac%7B%5Csqrt%5B5%5D%7Bx%5E%7B10%7D%7D%7D%7B%5Csqrt%5B5%5D%7B2%7D%7D%5Ccdot%5Cfrac%7B%5Csqrt%5B5%5D%7B2%5E4%7D%7D%7B%5Csqrt%5B5%5D%7B2%5E4%7D%7D%5C%5C%5C%5C%3D%5Cfrac%7Bx%5E%7B2%7D%5Csqrt%5B5%5D%7B16%7D%7D%7B%5Csqrt%5B5%5D%7B2%5E%7B5%7D%7D%7D%3D%5Cbf%7B%5Cfrac%7Bx%5E%7B2%7D%5Csqrt%5B5%5D%7B16%7D%7D%7B2%7D%7D)
The answer to the question is 7,516