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3 years ago

13

The length of AB¯¯¯¯¯ is 10 inches. A dilation with a scale factor of 25 is applied. What is the length of the image of AB

¯¯¯¯¯ ? Enter your answer in the box.

2 answers:

katen-ka-za [31]3 years ago

6 0

Pretty sure the answer is 4. Not 100% sure though

FromTheMoon [43]3 years ago

4 0

The answer is 4 Hope this helps :D

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Make a down payment of $1500 and finance the rest of $20000 at 1.9% interest rate, making equal monthly payments for 5 years.

pshichka [43]

We know that we have to m<span>ake a down payment of $1500 and finance the rest of $20000 at a 1.9% interest rate, making equal monthly payments for 5 years. Our first step to solve this problem would be to convert 5 years into months.

1 year = 12 months

12 * 5 = 60 months

Therefore, in 5 years there are 60 months.

Now lets solve this problem step by step.

Subtract the down payment from $20,000

</span>$20000-$1500=$18500

Multiply the remaining number by the interest rate.

$18500 *1.9 = $35150

Divide 35150 by number of months in 5 years (60)

$35150 / 60 = $585

<span>Therefore, you have to pay $585 per month. </span>

4 0

3 years ago

What is this answer?? : [6.6 ÷ (–5 + 3)] • (–1)

Mars2501 [29]

Your answer is 3.3

-Hope I helped you. :)

3 0

3 years ago

Factor completely 4x5 − 20x4 − 36x3.

lakkis [162]

Answer:

the 2nd one is the answer :)

8 0

3 years ago

-6x+4y=10<br> X-5y=-21<br> Please solve !

galina1969 [7]

X-5y=-21
x=-21+5y

-6(-21+5y)+4y=10
126+-30y+4y=10
126+-26y=10
-26y=-116
y=4.4615
x=1.3076

5 0

4 years ago

Find the number of elements in A1 ∪A2 ∪A3 if there are 100 elements in A1, 1000 in A2, and 10,000 in A3 if a) A1 ⊆ A2 and A2 ⊆ A

Stella [2.4K]

Answer:

Step-by-step explanation:

Given that there are 3 sets such that there are 100 elements in A1, 1000 in A2, and 10,000 in A3

a) If A1 ⊆ A2 and A2 ⊆ A3

then union will contain the same number of elements as that of A3

i.e. $n(A1 ∪A2 ∪A3)=n(A3) =10000$

b) If the sets are pairwise disjoint.

union will contain the sum of elements of each set

$n(A1 ∪A2 ∪A3) = 100+1000+10000=11100$

c) If there are two elements common to each pair of sets and one element in all three sets

We subtract common elements pairwise and add common element in 3

i.e. $n(A1 ∪A2 ∪A3) = 100+1000+10000-2-2-2+1\\= 10995$

5 0

3 years ago