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Softa [21]
3 years ago
6

Julio walks 35 miles at a speed of 4 mph. How long does it take him to walk that distance?

Mathematics
1 answer:
Verizon [17]3 years ago
7 0

Answer:the answer is 9

Step-by-step explanation:

36 divided by 4=9

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Which equation has the solution set x = (23) ?
Svet_ta [14]

Answer:

If you mean 2 and 3 it would be (x-2)(x-3)=0

Step-by-step explanation:

(x-2)=0

x-2=0 move the two on the other side to get positive

x=2

(x-3)=0

x-3=0 move the three on the other side to get positive

x=3

4 0
3 years ago
Verify experimentally that the angle opposite to the longer side is greater than
Veronika [31]

Answer:

If two sides of a triangle are unequal, the angle opposite to the longer side is larger (or greater). You may prove this theorem by taking a point P on BC such that CA = CP.

Step-by-step explanation:

That's how you can prove which side is bigger

6 0
3 years ago
Using the diagram, name a segment parallel to EH.<br><br> A. CD<br> B. AD<br> C. GH<br> D. BF
natima [27]
A segment parallel to EH is AD

answer
<span>B. AD</span>
4 0
3 years ago
A sweater that originally cost $40 is on sale for 10 percent off. What is the amount of the discount?
hichkok12 [17]
X percent = x/100
10 percent = 10/100 = 0.10

10% of $40 = 0.10*40 = 4

You save $4

The old price is $40 and changes to $36 after the discount is applied. This is ignoring any taxes or other surcharges

Anyways I'm going a bit off tangent. The final answer is choice B) $4
8 0
3 years ago
Read 2 more answers
A ball is thrown vertically upward from the top of a building 160 feet tall with an initial velocity of 48 feet per second. The
alina1380 [7]

Answer:

# after 5 seconds, the ball strikes the ground

# The ball reaches maximum height at t = 1.5 seconds

# The max height is 196 feet

Step-by-step explanation:

The equation is:

d(t)=-16t^2+48t+160

t is the time

d(t) is the distance traveled

Initial height is 160 feet and initial velocity is 48 ft/sec

If we want to find the time it takes the ball to hit the ground, we let d(t) equal to 0 and find t. Shown below:

-16t^2+48t+160=0\\t^2-3t-10=0\\(t-5)(t+2)=0\\t=5,-2

We disregard t = -2 since time can't be negative. We take t = 5

Thus, after 5 seconds, the ball strikes the ground.

The equation is a quadratic of the form: ax^2+bx+c

Matching equations, we can say:

a = -16

b = 48

c = 160

The time when ball reaches max height is given as:

t=-\frac{b}{2a}

Substituting, we find:

t=-\frac{b}{2a}\\t=-\frac{48}{2(-16)}\\t=1.5

The ball reaches maximum height at t = 1.5 seconds

The max height can be found by putting t = 1.5 into the original equation. Shown below:

d(t)=-16t^2+48t+160\\d(1.5)=-16(1.5)^2+48(1.5)+160\\=196

The max height is 196 feet

8 0
3 years ago
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