Mathematics I need help please

Aileen has 10 apples. How many apples will there be in 7 boxes?

Marysya12 [62]

The answer should be 1 because you can’t box up pieces of apples to divide it perfectly into a box. It matters that each box has a full apple!! Hope this makes sense!!

8 0

4 years ago

a student used his place value chart to show a number after the teacher instructed him to divide his number by 100 the chart sho

Anna35 [415]

A student divided the given number by 100 that resulted to 28.003 in his chart. So what we are looking for this situation is the value of the number before it was divided by 100.
To get the value, simply multiply the result by 100
=> 28.003 x 100
=> 2800.3
by dividing 100 to the given number, we simply move the value to the right in a value of hundreds.
See attached Image.

8 0

4 years ago

I need help with this problem from the calculus portion on my ACT prep guide

LenaWriter [7]

Given a series, the ratio test implies finding the following limit:

$\lim _{n\to\infty}\lvert\frac{a_{n+1}}{a_n}\rvert=r$

If r<1 then the series converges, if r>1 the series diverges and if r=1 the test is inconclusive and we can't assure if the series converges or diverges. So let's see the terms in this limit:

$\begin{gathered} a_n=\frac{2^n}{n5^{n+1}} \\ a_{n+1}=\frac{2^{n+1}}{(n+1)5^{n+2}} \end{gathered}$

Then the limit is:

$\lim _{n\to\infty}\lvert\frac{a_{n+1}}{a_n}\rvert=\lim _{n\to\infty}\lvert\frac{n5^{n+1}}{2^n}\cdot\frac{2^{n+1}}{\mleft(n+1\mright)5^{n+2}}\rvert=\lim _{n\to\infty}\lvert\frac{2^{n+1}}{2^n}\cdot\frac{n}{n+1}\cdot\frac{5^{n+1}}{5^{n+2}}\rvert$

We can simplify the expressions inside the absolute value:

$\begin{gathered} \lim _{n\to\infty}\lvert\frac{2^{n+1}}{2^n}\cdot\frac{n}{n+1}\cdot\frac{5^{n+1}}{5^{n+2}}\rvert=\lim _{n\to\infty}\lvert\frac{2^n\cdot2}{2^n}\cdot\frac{n}{n+1}\cdot\frac{5^n\cdot5}{5^n\cdot5\cdot5}\rvert \\ \lim _{n\to\infty}\lvert\frac{2^n\cdot2}{2^n}\cdot\frac{n}{n+1}\cdot\frac{5^n\cdot5}{5^n\cdot5\cdot5}\rvert=\lim _{n\to\infty}\lvert2\cdot\frac{n}{n+1}\cdot\frac{1}{5}\rvert \\ \lim _{n\to\infty}\lvert2\cdot\frac{n}{n+1}\cdot\frac{1}{5}\rvert=\lim _{n\to\infty}\lvert\frac{2}{5}\cdot\frac{n}{n+1}\rvert \end{gathered}$

Since none of the terms inside the absolute value can be negative we can write this with out it:

$\lim _{n\to\infty}\lvert\frac{2}{5}\cdot\frac{n}{n+1}\rvert=\lim _{n\to\infty}\frac{2}{5}\cdot\frac{n}{n+1}$

Now let's re-writte n/(n+1):

$\frac{n}{n+1}=\frac{n}{n\cdot(1+\frac{1}{n})}=\frac{1}{1+\frac{1}{n}}$

Then the limit we have to find is:

$\lim _{n\to\infty}\frac{2}{5}\cdot\frac{n}{n+1}=\lim _{n\to\infty}\frac{2}{5}\cdot\frac{1}{1+\frac{1}{n}}$

Note that the limit of 1/n when n tends to infinite is 0 so we get:

$\lim _{n\to\infty}\frac{2}{5}\cdot\frac{1}{1+\frac{1}{n}}=\frac{2}{5}\cdot\frac{1}{1+0}=\frac{2}{5}=0.4$

So from the test ratio r=0.4 and the series converges. Then the answer is the second option.

8 0

2 years ago

I needddddddd helpppppppppp

ale4655 [162]

Answer:

x = 142°

Step-by-step explanation:

The first thing you need to figure out is the missing interior angle of the triangle.

There is 180 degrees in a triangle, there is a 90° and 52° angle listed, so subtract that from 180° to get the missing angle.

180° - 90° - 52° = 38°

Now we want the exterior angle x. Angle x and the interior angle form a straight line when combined which will also be a 180° angle. You can picture this as a half circle (a full circle is 360°).

So subtract the interior angle 38° from 180°

180° - 38° = 142°

3 0

3 years ago

What is the zero of g(x)=-x-7? A. 7 B. 4 C. -7 D. 3

blsea [12.9K]

Answer:

I think it's A. 7

Step-by-step explanation:

4 0

3 years ago