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4 years ago

Mathematics I need help please

Mathematics

1 answer:

Mkey [24]4 years ago

3 0

Here you go! Good luck :)

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(Lots of points)PLEASE HELP ME Due today at 8:59 in Texas

IceJOKER [234]

Answer:

6.) So 8 of 24 hours is 1/3. So the percent of his time used was <u><em>33.33333 . . %</em></u> (etc)

7.) The easiest way to figure out a percentage is dividing it. So if it was 30 hit out of 75 people, then divide 30 by 75. So <u><em>40%</em></u> of them got hit.

Hope that helps

6 0

3 years ago

Find the slope of the line containing the pair of points. (7,4) and (6,-9)

lesya [120]

Answer:

Step-by-step explanation:

We can use the slope formula to find the slope

m = ( y2-y1)/(x2-x1)

= ( -9-4)/(6-7)

= -13/-1

= 13

3 0

3 years ago

Read 2 more answers

A pet store has 150

trasher [3.6K]

Answer:

Step-by-step explanation:

hope this helps loves x

4 0

2 years ago

Which figure has the same area as the parallelogram shown below? A. A triangle with a base of 4 mm and a height of 20 mm B. A tr

Arisa [49]

<h2>Answer: A trapezoid with bases of 6 mm and 14 mm and a height of 8 mm </h2>

The parallelogram in the figure has an area of $80mm^{2}$ , according to the following formula, which works for all rectangles and parallelograms:

$A_{parallelogram}=(b)(h)$ (1)

Where $b$ is the base and $h$ is the height

The<u> area of a triangle</u> is given by the following formula:

$A_{triangle}=\frac{1}{2}(b)(h)$ (2)

So, for option A:

$A_{triangle}=\frac{1}{2}(4mm)(20mm)=40mm^{2} \neq 80mm^{2}$

Now, the <u>area of a trapezoid </u>is:

$A_{trapezoid}=\frac{1}{2}(b_{1}+ b_{2})(h)$ (3)

For option B:

$A_{trapezoid}=\frac{1}{2}(15mm+25mm)(2 mm)=40mm^{2} \neq 80mm^{2}$

For option C:

$A_{trapezoid}=\frac{1}{2}(6mm+14mm)(8 mm)=80mm^{2}$ >>>>This is the correct option!

For option D:

$A_{rectangle}=(30mm)(8mm)=240mm^{2} \neq 80mm^{2}$

<h2>Therefore the correct option is C</h2>

5 0

3 years ago

you can speed from 0 to 25 m/s in 25 seconds and your friend can speed up from 0 to 6 m/s in 6 seconds. who is faster

aksik [14]

Answer:

Neither; see below

Step-by-step explanation:

Your acceleration: $a=\frac{\Delta v}{\Delta t}=\frac{25-0}{25}=1m/s^2$

Your friend's acceleration: $a=\frac{\Delta v}{\Delta t}=\frac{6-0}{6}=1m/s^2$

Therefore, since both you and your friend accelerate at the same rate, neither is faster.

7 0

3 years ago