Answer:
The ratio of the drag coefficients is approximately 0.0002
Step-by-step explanation:
The given Reynolds number of the model = The Reynolds number of the prototype
The drag coefficient of the model, = The drag coefficient of the prototype,
The medium of the test for the model, = The medium of the test for the prototype,
The drag force is given as follows;
We have;
Therefore;
= (1/17)^3 ≈ 0.0002
The ratio of the drag coefficients ≈ 0.0002.
Answer:
340 degrees
Step-by-step explanation:
So the key thing here is to notice that we are given the circumference which will allow us to find a value for the radius of the circle and hence the angle subtended by the arc (the central angle).
So the circumference of a circle = 2pi(r)
This means:
6 = 2pi(r)
Which means that
r = 6/2pi or r = 3/pi
Now we can use this value of r to find our angle in conjunction with the value of the arc length. So:
Arc length is defined by: length = θr
Where θ is our angle value.
So lets plug in:
Multiply by pi to get:
Divide by 3 to get that:
θ = 17pi/9
So if we convert that from radians to degrees we get 340 degrees.