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Ksivusya [100]
3 years ago
15

The weight, in pounds, of a newborn baby tt months after birth can be modeled by the function W(t)=1.25t+6.W(t)=1.25t+6. What is

the yy-intercept of the function and what is its interpretation in the context of the problem?
Mathematics
1 answer:
ollegr [7]3 years ago
8 0

Answer:

6

Step-by-step explanation:

GIVEN: The weight, in pounds, of a newborn baby t months after birth can be modeled by the function W(t)=1.25t+6.

TO FIND: What is the y-intercept of the function and what is its interpretation in the context of the problem.

SOLUTION:

in  W(t)=1.25t+6

if t=0

W(0)=6

Hence y-intercept is 6

the y-intercept in this represents the weight of baby just after he is born.

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Kobotan [32]

Answer:

1. 17.73 or 17 \frac{11}{15} or \frac{266}{15}

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Step-by-step explanation:

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3 years ago
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Taya2010 [7]

Answer:

The height of the pyramid is 6\ cm

Step-by-step explanation:

we know that

The volume of the pyramid is equal to

V=\frac{1}{3}Bh

where B is the area of the base of the pyramid

h is the height of the pyramid

we have

V=12\ cm^{3}

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4 years ago
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Svetlanka [38]
The answer should be 25.64$
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6 0
3 years ago
Read 2 more answers
Differentiating Exponential functions In Exercise,find the derivative of the function. See Example 2 and 3.
Alecsey [184]

Answer: -2xe^{-x^2}

Step-by-step explanation:

Let u be a differentiable function , then

\dfrac{d}{dx}(e^x)=e^x

\dfrac{d}{dx}e^u=e^u\dfrac{du}{dx}              (1)

Given function : y = e^{-x^2}

Differentiate both sides with respect to x , we get

y'=e^{-x^2}\dfrac{d(-x^2)}{dx}  (By using  (1))

\Rightarrow\ y'=e^{-x^2}(-2x)  [∵ \dfrac{d}{dx}(x^n)=x^{n-1}]

\Rightarrow\ y'=-2xe^{-x^2}

Hence, the derivative of the given function is -2xe^{-x^2} .

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3 years ago
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Stells [14]

Answer:

The formula for area is length times width.

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4 0
3 years ago
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