Answer:
Yes, it is 368.24, because you cannot use a digit more than once.
Step-by-step explanation:
The given equation is
![\begin{gathered} \log (x^4+3x^3)-\log (x+3)+\log 2-\log 6=2\log x \\ \log (\frac{x^4+3x^{3^{}}}{x+3})+\log \frac{2}{6}=\log x^2 \\ \log \frac{x^3(x+3)}{x+3}+\log \frac{1}{3}=\log x^2 \\ \log x^3+\log \frac{1}{3}=\log x^2 \\ \log \frac{x^3}{3}=\log x^2 \\ \frac{x^3}{3}=x^2 \\ x^3-3x^2=0 \\ x^2(x-3)=0 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Clog%20%28x%5E4%2B3x%5E3%29-%5Clog%20%28x%2B3%29%2B%5Clog%202-%5Clog%206%3D2%5Clog%20x%20%5C%5C%20%5Clog%20%28%5Cfrac%7Bx%5E4%2B3x%5E%7B3%5E%7B%7D%7D%7D%7Bx%2B3%7D%29%2B%5Clog%20%5Cfrac%7B2%7D%7B6%7D%3D%5Clog%20x%5E2%20%5C%5C%20%5Clog%20%5Cfrac%7Bx%5E3%28x%2B3%29%7D%7Bx%2B3%7D%2B%5Clog%20%5Cfrac%7B1%7D%7B3%7D%3D%5Clog%20x%5E2%20%5C%5C%20%5Clog%20x%5E3%2B%5Clog%20%5Cfrac%7B1%7D%7B3%7D%3D%5Clog%20x%5E2%20%5C%5C%20%5Clog%20%5Cfrac%7Bx%5E3%7D%7B3%7D%3D%5Clog%20x%5E2%20%5C%5C%20%5Cfrac%7Bx%5E3%7D%7B3%7D%3Dx%5E2%20%5C%5C%20x%5E3-3x%5E2%3D0%20%5C%5C%20x%5E2%28x-3%29%3D0%20%5Cend%7Bgathered%7D)
hence
![x=0\text{ or x=3}](https://tex.z-dn.net/?f=x%3D0%5Ctext%7B%20or%20x%3D3%7D)
But x cannot be zero so x=3
So the value of x is 3
h
Answer:
It's 15.70796. Won't go in-depth since time seems to be of the essence
Step-by-step explanation:
Won't go in-depth since time seems to be of the essence
11 and -28
11x-28=-308
11+-28=-17