The Best Answer :
<span>"G2 phase is the third, final, and usually the shortest subphase during interphase within the cell cycle in which the cell undergoes a period of rapid growth to prepare for mitosis. It follows successful completion of DNA synthesis and chromosomal replication during the S phase, and occurs during a period of often four to five hours. This far into interphase the nucleus is well defined, bound by a nuclear envelope and contains at least one nucleolus. Although chromosomes have been replicated they cannot yet be distinguished individually because they are still in the form of loosely packed chromatin fibers. The G2 phase prepares the cell for mitosis (M phase) which is initiated by prophase.
At the end of this gap phase is a control checkpoint (G2 checkpoint) to determine if the cell can proceed to enter M phase and divide. The G2 checkpoint prevents cells from entering mitosis with DNA damaged since the last division, providing an opportunity for DNA repair and stopping the proliferation of damaged cells. Because the G2 checkpoint helps to maintain genomic stability, it is an important focus in understanding the molecular causes of cancer."</span>
Answer:area of grass and trees and other vegetation
Explanation:set apart for recreational use or aesthetic purposes in urban environments
It's a pyramid of numbers, I believe.
Fixation during which the enzyme RuBisCO incorporates (fixes) carbon-dioxide into 3-PGA; 2. Reduction during which 3-PGA is reduced using NADPH as electron supply; 3. Regeneration during which RuBP<span> is regenerated so the cycle can start again.</span>
Answer:
45 g of the solid Tris will be dissolved in 2.5 liters of water.
Explanation:
Recall that:
<em>Number of moles = molarity x volume</em>
Hence, number of moles of Tris present in 2.5 liters, 150 mM solution:
= 150/1000 x 2.5 = 0.375 moles
Also, recall that:
<em>No of moles of substance = mass/molar mass.</em>
Hence, mass of 0.375 moles substance:
= no of moles of the substance x molar mass of the substance.
= 0.375 x 120 = 45 g.
Therefore, in order to prepare 2.5 liters, 150 mM of an aqueous solution of Tris, 45 g of the solid Tris will be dissolved in 2.5 liters of water.
