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ANTONII [103]
3 years ago
10

Is equivalent to 4sqrt(27) + 3sqrt(12) 18sqrt(3) 7sqrt(3) 5sqrt(3) 7sqrt(39)

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
3 0
When you say sweet what does it equal
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3&lt;3x+6&lt;24<br><br>i keep getting 1 &lt; x &lt; 6<br>but the answer says -1 &lt; x &lt; 6
lara [203]
3 < 3x+6
-3<3x
-1<x

3x+6<24
3x<18
x<6

-1<x<6 the book is right

6 0
3 years ago
Find all points on the curve y = cos x, 0 ≤ x ≤ 2π, where the tangent line is parallel to the line y = -x.
andre [41]

Answer:

90⁰

Step-by-step explanation:

y=cosx

y'= -sinx

eqñ of tangent is y=-x

slope of tangent =-1

we know...

slope of tangent = y' or derivative of y

-sin x = -1

sin x= 1

x = 90⁰

7 0
3 years ago
6×10(6)+7×10(5)+3×10(2)+8×10+2
anastassius [24]

Answer:

852

6×10(6)+7×10(5)+3×10(2)+8×10+2= 852

Step-by-step explanation:

ORDER OF OPERATIONS Will really help you solve this long problem.

Order of operations is PEMDAS.

P-parenthesis

E-exponents

M-multiplication

D-division

A-addition

S-subtraction

6)(10)(6)+(7)(10)(5)+(3)(10)(2)+(8)(10)+2

=(60)(6)+(7)(10)(5)+(3)(10)(2)+(8)(10)+2

=360+(7)(10)(5)+(3)(10)(2)+(8)(10)+2

=360+(70)(5)+(3)(10)(2)+(8)(10)+2

=360+350+(3)(10)(2)+(8)(10)+2

=710+(3)(10)(2)+(8)(10)+2

=710+(30)(2)+(8)(10)+2

=710+60+(8)(10)+2

=770+(8)(10)+2

=770+80+2

=850+2

=852

7 0
3 years ago
After spending some time looking for his pump, Marlon pumps up an uninflated balloon, pumping air into it at a constant rate. He
galina1969 [7]

Answer:

Graph D

Step-by-step explanation:

Initially, Marlon was looking for his pump. Thus, no air was pumped into the balloon until he got the pump. On getting the pump, he inflated the balloon with air at a constant rate, after which he tied it with a string to prevent the air from escaping.

The analysis is that, at the time he decided to inflate the balloon till he got a pump, the volume of air in the balloon is zero with respect to time. Pumping air at a steady rate into the balloon increases the volume of air flowing into it gradually and steadily.

When the volume got to a definite amount, he stopped pumping air and tied with a string. Thus, the volume of air in the balloon remains constant.

8 0
3 years ago
S=<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bn%7D%7B2%7D%20" id="TexFormula1" title=" \frac{n}{2} " alt=" \frac{n}{2} "
dmitriy555 [2]

\bf S=\cfrac{n}{2}(a+I)\implies S=\cfrac{n(a+I)}{2}\implies 2S=n(a+I)\implies \stackrel{\textit{distributing}}{2S=na+nI} \\\\\\ 2S-nI=na\implies \cfrac{2S-nI}{n}=a

8 0
3 years ago
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