There are 3 possibilities when choosing 1 of 3 books. There are 8 possibilities when choosing 1 of 8 books. Events are independent of each other so "and" would be to multiply. 3 × 8 = 24 possible combinations
You can also see by writing out the possibilities.. Say names of books are {A,B,C} and names of CD's are {1,2,3,4,5,6,7,8} A1, A2, A3, A4, A5, A6, A7, A8 B1, B2, B3, B4, B5, B6, B7, B8 C1, C2, C3, C4, C5, C6, C7, C8
Let's solve your equation step-by-step. <span><span><span><span>4<span>x^2</span></span>+<span>28x</span></span>−32</span>=0 </span>Step 1: Factor left side of equation. <span><span><span>4<span>(<span>x−1</span>)</span></span><span>(<span>x+8</span>)</span></span>=0 </span>Step 2: Set factors equal to 0. <span><span><span>x−1</span>=<span><span><span>0<span> or </span></span>x</span>+8</span></span>=0 </span><span><span>x=<span><span>1<span> or </span></span>x</span></span>=<span>−<span>8</span></span></span>