Answer:
two real, unequal roots
Step-by-step explanation:
This is a quadratic equation. The quadratic formula can be used to determine how many and what kind of roots may exist:
Find the discriminant, which is defined as b^2 - 4ac, if ax^2 + bx + c = 0. In this case, a = 1, b = -2 and c = -8, so that the discriminant value is
(-2)^2 - 4(1)(-8), or 4 + 32 = 36.
Because the discriminant is real and positive, we know for certain that we have two real, unequal roots
it depends what the number is
Answer:
yeah
Step-by-step explanation:
its basically looks good, if your teacher gives a bad grade than idk, but looks about right :)
2 beginner, 6 intermediate, 3 advanced...total of 11
P(advanced) = 3/11
replaced
P(beginner) = 2/11
P(both) = 3/11 * 2/11 = 6/121 <=
Answer:
-6x+11
Step-by-step explanation: