Similar-looking organisms, such as the dogs shown below, that can interbreed and produce fertile offspring are called

I need help...............

kipiarov [429]

Answer:

look at google

Explanation:

5 0

3 years ago

I am a circulating cell involved in ige type allergic reactions. i am a mediator of allergic reactions because i can release gra

777dan777 [17]

Answer:

I am a basophil.

Further information:

Basophil:

Basophils are a type of white blood cell. Basophils are the smallest common of the granulocytes, representing about 0.5 to 1% of circulating white blood cells. Yet, they are the major type of granulocyte.

Function of basophil:

They are accountable for inflammatory reactions during immune response, as well as in the development of acute and chronic allergic diseases, including anaphylaxis, asthma, atopic dermatitis and hay fever. They also yield compounds those co-ordinate immune responses, including histamine and serotonin that induce inflammation, heparin that stops blood clotting, although there are less than that found in mast cell granules.

Basophils may present in many specific types of inflammatory reactions, specially those that cause allergic symptoms. Basophils have anticoagulant heparin, which prevents blood from clotting too rapidly. They also have the vasodilator histamine, which promotes blood flow to tissues.

Structure of Basophil:

Basophils comprise large cytoplasmic granules which vague the cell nucleus under the microscope when stained. However, when unspotted, the nucleus is visible and it usually has two lobes. The Mast cell which is another granulocyte has very like in appearance and function. Both cell types store histamine, a chemical that is secreted by the cells when inspired. However, they arise from different branches of hematopoiesis, and mast cells usually do not circulate in the blood stream, but instead are located in connective tissue. Similar to all circulating granulocytes, basophils can be carried out of the blood into a tissue when we need it.

Answer details:

Subject: Biology

Level: High level

Keywords:

• Basophil

• Function of Basophil

• Structure of Basophil

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Andesitic rock is an igneous rock with a composition in between that of basaltic and granitic igneous rock. true or false.

FinnZ [79.3K]

Its false..................

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3 years ago

Some scientists theorize that continental movements may cause climate changes by _____.

PolarNik [594]

Answer: Changing Patterns Of Ocean Currents Is The Correct Answer.

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4 years ago

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Albino rabbits (lacking pigment) are homozygous for the recessive c allele (C allows pigment formation). Rabbits homozygous for

Arisa [49]

Answer:

a. If the b and c loci were unliked the expected phenotypic proportions would be:

- 1/4 Brown

- 1/4 Black

- 1/2 Albino

b. The estimated distance between the two loci is equal to 17 centimorgans (cM).

Explanation:

a. If the loci b and c are unlinked or they are not in the same chromosome, it means that b and c are segregated independently (following Mendel's laws). So, the first step is to state the genotypes of the rabbits.

Albino rabbits are homozygous for c (cc)

Brown rabbits are homozygous for b (bb).

Black rabbits have a copy of B (Bb or BB).

But, rabbits have the two genes (b and c), so they could be:

Albino: BBcc/Bbcc/bbcc.

Brown: bbCC/bbCc

Black: BBCC/BBCc/BbCC/BbCc

A cross was made with true-breeding brown rabbits( that means "pure" or homocygotes) bbCC and albino BBcc.

So, we have :

bbCC X BBcc

This is a dihybrid cross with only one possible genotype in F1: BbCc. -> Black rabbits.

After this, these rabbits (BbCc) were crossed with double recessive (albino) rabbits, like this:

BbCc X bbcc

To know the possible outcomes of F2, it is necessary to make a Punnett square 4x4. Following the independent assortment principle, we will have the following possible gametes:

Black Rabbits: Cb, CB, cB,cb.

Double recessive rabbits: cb, cb, cb, cb.

After doing the Punnett square, we will have 4 possible genotypes and 3 possible phenotypes in F2:

1. bbCc = Brown

2 BbCc = Black

3. Bbcc= Albino

4. bbcc= Albino

That means:

1. 1/4 Brown

2. 1/4 Black

3. 1/2 Albino

b. To estimate the distance between the two loci is necessary to use the data provided in the question.

In this case, we are assuming that b and c are in the same chromosome, so they don't follow Mendel's laws. The first step is to know which are the initial genotypes.

The initial cross was between a brown rabbit (bbCC ) and an albino rabbit (BBcc). If the two genes are linked, we can say that in the brown rabbit bC are always together and in the albino Bc will be together, because they're linked.

F1 will be black rabbits bCBc, (remember bC and Bc go always together).

So, after this, a new cross was made with a double recessive:

bCBc X bcbc

The possible outcomes are:

bCbc Brown

Bcbc Albino

As you see, there are not black rabbits, so to find black rabbits, we need to find a BCbc genotype. This genotype can be produced by recombination or crossingover in the same chromosome in parentals. So, the distance between two loci is equal to the proportion of individuals with a recombinant genotype, in this case, BCbc or black rabbits.

So, we have:

34 black

66 brown

100 albino

Total: 200

D $Distance=\frac{Recombinants}{Total } *100= \frac{34}{200}*100= 17 cM$

Estimated distances are measured in centimorgans (cM).

4 0

4 years ago