Answer:
The activity that does not represent a beneficial contribution made by biologists is to improve the durability of non-stick coatings (option C).
Explanation:
The development and improvement of non-stick coatings does not correspond to an activity within the field of biology. Anti-stick coatings, such as Teflon, are products developed through industrial activity.
Biologists' activity is focused on living organisms and their interaction with the surrounding environment. Improving arable soils and food quality, as well as increasing life expectancy are activities that fall within the field of study of biology and its related disciplines.
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The mix of alleles from various genes that end up in the daughter cells is determined by the anaphase 1 of meiosis 1.
Chromosome segregation during meiosis is mirrored in the segregation of alleles. During anaphase, 1 of meiosis 1 homologous chromosomal separation leads to allele segregation.
Chromosomes display autonomous assortment when they are randomly split into daughter cells during meiosis.
<h3>What takes place in anaphase 1?</h3>
During meiosis I, sister chromatids remain together as homologous chromosomes separate. To appreciate the development of germ cells, it is crucial to comprehend how this odd chromosomal segregation behavior came to be. Here, we show that the pattern of chromosomal segregation during meiosis I is determined by the microtubule-kinetochore interactions that are inhibited during prophase I and the premeiotic S phase.
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It helps us categorize organisms so we can more easily communicate biological information. Taxonomy uses hierarchical classification as a way to help scientists understand and organize the diversity of life on our planet.
Th answer is D its the best answer that fits the question .
Answer and Explanation:
<u>Cross:</u> aa Bb dd Ee x AA bb Dd Ee
We can calculate the probability of getting heterozygous individuals in the progeny by using the <u>product rule</u>. Assuming that these four genes <u>assort independently</u> (<em>events that occur independently from each other</em>), we can infer that the F1 will have the next genotypic proportions for each gene:
1) aa x AA
F1) 4/4=1 Aa
2) Bb x bb
F1) ½ bb
½ Bb
3) dd x Dd
F1) ½ dd
½ Dd
4) Ee x Ee
F1) ¼ EE
2/4 = ½ Ee
¼ ee
So, to know what the probability is that the F1 of being heterozygous for all loci, we must multiply the respective individual probabilities of getting a heterozygous genotype, like this:
1 Aa x ½ Bb x ½ Dd x ½ Ee = 1/8 AaBbDdEe
