It would be 1/3rd because your last number would be 4 in the equation of 12 sandwiches.
Answer:
y = -1/2x + 17/2
Explanation:
y = 2x + 1 is in slope intercept form
in the equation y = mx+b, m is the slope, and in the equation m =2
the slope of a perpendicular line is the negative reciprocal of the other slope.
slope of perpendicular= -1/m = -1/2
y = -1/2x + b
now find b by substituting in (1,8) into the partial equation
8 = -1/2 + b
b = 8+ 1/2
b = 17/2
please give thanks :) hope this helps
Answer:
45.650 centimeters
Step-by-step explanation:
The height of a vase is 45.7 centimeters when rounded to the nearest tenth of a centimeter. What is the shortest possible height of the vase? Give your answer to 3 decimal places
Given that :
Height of vase = 45.7 when rounded to the nearest tenth
The shortest possible height of the vase : will be 45.65, this is because, the subsequent digit (hundredth) after the tenth digit is the figure rounded to give a tenth digit of 7
From the we know that the tenth digit before rounding is 7 - 1 = 6
And smallest possible value the hundredth placed digit could have in other to be rounded to 1 is 5.
To three decimal place, the thousandth placed value could take the least possible value in a digit series, which is 0
Hence, the shortest possible height of the vase = 4.650
Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
