In order to be differentiable everywhere, 
must first be continuous everywhere, which means the limits from either side as 
must be the same and equal to 
. By definition, 
, and
so we need to have 
.
For to be differentiable at 
, the derivative needs to be continuous at , i.e.
We then need to have
Then
Answer:
im sorry it does not show the picture i hope you find help
Step-by-step explanation:
The answer to this question is 59.2, Hope this helps you
Answer:
y = 6.5 units
Step-by-step explanation:
Let L be the length of sides of the square.
Given the following data;
Perimeter of square = 8y - 12
Area of square = 100 square units
To find the value of y;
Area of a square = L²
Substituting into the formula, we have;
100 = L²
L = √100
L = 10 units
Mathematically, the perimeter of a square is given by the formula;
Perimeter of a square = 4L
Substituting into the formula, we have;
8y - 12 = 4*10
8y - 12 = 40
8y = 40 + 12
8y = 52
y = 52/8
y = 6.5 units
