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katrin2010 [14]
3 years ago
9

Can someone help me plzzzz

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
8 0

Answer:

279 feet

Step-by-step explanation:

To find x, we solve using the Trigonometric function of Tangent

tan θ = Opposite/ Adjacent

θ = 64°

Length of the shadow = Adjacent = 136 feet

Height of the building = Opposite = h

Hence,

tan 64 = h/136 feet

Cross Multiply

h = tan 64 × 136 feet

h = 278.84132245 feet

Approximately, h to the nearest foot ≈ 279 feet

Therefore, the height of the building = 279 feet

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A bag contains 8 white, 4 red, 7 green, and 5 blue marbles. Eight marbels are withdrawn randomly. How many withdrawn marbles wer
Wewaii [24]

We are starting with 8+4+7+5=24 marbles. We're taking out 8, so we'll be left with 24-8=16 marbles. Think about those 16. If the probability of drawing a white one is 1 in 4, that means that 1/4 of the marbles are white. 1/4 of 16 is 16/4 = 4 marbles are white. Since we started with 8 white, and there are 4 left, we must have taken out 8-4 = 4 white marbles.

7 0
3 years ago
Which equation is written in standard form?
ludmilkaskok [199]

Answer: D

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
The sum of a number and 19 is at least 8.3 what is the inequality and solution
OverLord2011 [107]
X + 19 ≥ 8.3       <<< your inequality equation

x ≥ 8.3 - 19

x ≥ -10.7    << your solution

hope this helps, God bless!
6 0
3 years ago
HELP PLEASE!!
cestrela7 [59]

Answer:

Quadrilateral FSHB∼quadrilateral KTWJ.

Step-by-step explanation:

Given two quadrilaterals we have to prove these two similar.

The two quadrilaterals are similar if the corresponding sides of these are proportional then only the quadrilateral are proportional i.e

∴ \frac{FS}{KT}=\frac{SH}{TW}=\frac{HB}{WJ}=\frac{BF}{JK}

If the above condition satisfied then the quadrilateral are similar.

Let us find these ratios

\frac{FS}{KT}=\frac{28}{21}=1.333

\frac{SH}{TW}=\frac{24}{18}=1.333

\frac{HB}{WJ}=\frac{18}{13.5}1.333

\frac{BF}{JK}=\frac{18}{13.5}1.333

All ratios are equal.

Hence, the corresponding sides and angles of these two quadrilaterals are proportional implies that these two are similar i.e quadrilateral FSHB∼quadrilateral KTWJ.




7 0
3 years ago
Read 2 more answers
The answer please. (F-g)(-3)
ad-work [718]
There are two ways to do this
Method 1:

Find (f-g)(x) first
(f-g)(x) = f(x) - g(x)
(f-g)(x) = (5x^2+3) - (-2x+4)
(f-g)(x) = 5x^2+3+2x-4
(f-g)(x) = 5x^2+2x-1

Then plug in x = -3
(f-g)(-3) = 5(-3)^2+2(-3)-1
(f-g)(-3) = 5(9)+2(-3)-1
(f-g)(-3) = 45-6-1
(f-g)(-3) = 39-1
(f-g)(-3) = 38

-----------------------------------------

Method 2:

Find f(-3)
f(x) = 5x^2+3
f(-3) = 5(-3)^2+3
f(-3) = 5(9)+3
f(-3) = 45+3
f(-3) = 48

Find g(-3)
g(x) = -2x+4
g(-3) = -2(-3)+4
g(-3) = 6+4
g(-3) = 10

Subtract the two results
(f-g)(-3) = f(-3) - g(-3)
(f-g)(-3) = 48 - 10
(f-g)(-3) = 38

-----------------------------------------

Whichever method you pick, the answer is: 38

4 0
4 years ago
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