Answer:
The probability that an elementary or secondary school teacher selected at random from this city is a female or holds a second job is 0.90.
Step-by-step explanation:
Denote the events as follows:
<em>X</em> = an elementary or secondary school teacher from a city is a female
<em>Y</em> = an elementary or secondary school teacher holds a second job
The information provided is:
P (X) = 0.66
P (Y) = 0.46
P (X ∩ Y) = 0.22
The addition rule of probability is:
Use this formula to compute the probability that an elementary or secondary school teacher selected at random from this city is a female or holds a second job as follows:
Thus, the probability that an elementary or secondary school teacher selected at random from this city is a female or holds a second job is 0.90.
We need to solve -3x+4y=12 for x
Let's start by adding -4y to both sides
-3x+4y-4y=12-4y
-3x=-4y+12
x = (-4y+12)/-3
x= 4/3 y -4
Now substitute 4/3 y -4 for x in 1/4 x - 1/3 y =1
1/4 x -1/3 y =1
1/4 (4/3 y -4) -1/3 y =1
Use the distributive property
(1/4)(4/3 y) + (1/4)(-4) -1/3 y =1
1/3 y -1 - 1/3 y =1
Now combine like terms
(1/3y -1/3y) + (-1) =1
= -1
-1 = 1
Now add 1 to both sides
0=2
So there are no Solutions
The answer is C
I hope that's help Will :)
Multiple both ratios by a least common denominator
the least common denominator for both is 15
multiply the first ratio by 3/3
9/15=9/15
both are equal because when multiplying by the least common denominator you get the same answer
Answer:
C. x =3
Step-by-step explanation:
Extraneous solution is that root of a transformed equation that doesn't satisfy the equation in it's original form because it was excluded from the domain of the original equation.
Let's solve the equation first
Hence, we can conclude that x=3 is an extraneous solution of the equation ..
Problem 1 Answer: x = 2/3y+8
Show Work:
Step 1: Add 2y to both sides.
3x−2y+2y=24+2y
3x=2y+24
Step 2: Divide both sides by 3.
3x/3 = 2y+24/3
x = 2/3y+8
Problem 2 Answer: x=−2y+48
Show Work:
Add -2y to both sides.
x+2y+−2y=48+−2y
x=−2y+48
