Equation=2a+3b=$14
=4a+5b=$24
Multiply the first equation by 4 and the second by 2 to get the value of b....
8a+12b=56 -
8a+10b=48
2b=8
b=$4
If the price of an orange is $4 we can now find the price of an apple by
.................2a+(3*$4)=$14
............2a+12=14........2a=2
a=1
So the cost of an apple is $1 and that of an orange is $4
......Hope it helps you
Answer:
The first question is (n*8) - 4
The second question is no.
Step-by-step explanation:
The first question, you add 8. The first is 1. 1 * 8 = 8 - 4 = 4.
Therefore, the equation is (n*8) - 4
The second question, you can plug in numbers. You can solve for a term. -100 + 17 = -83. -83 is not a multiple of -4. -100 is not a term.
Answer: (v + 7)(v -3)
Step-by-step explanation:
(v +7)(v -3)
v x v = v^2
v x -3 = -3v
7 x v = 7v
7 x -3 = -21
v^2 -3v +7v -21 = v^2 +4v -21 = 0
Answer:
The speed of jogger in uphills is 4 mile per hour
And The speed of jogger in downhills is 10 mile per hour
Step-by-step explanation:
Given as :
The distance cover by jogger in downhill (Dd) = 5 miles
The distance cover by jogger in uphill (Du) = 2 miles
The time taken by jogger in downhill (Td) = T hour
The time taken by jogger in uphill (Tu) = T hour
Let The speed of jogger in uphills (Su) = x mph
So ,The speed of jogger in downhills (Sd) =( x + 6 ) mph
∵, Time =
So, Tu =
Or, T =
h
And Td =
Or, T =
h
∵ Time duration of both is same
∴
= 
Or, 2 × (x + 6) = 5x
Or, 2x + 12 = 5x
So, 12 = 3x
∴ x =
= 4 mph
And x + 6 = 4 + 6 = 10 mph
Hence The speed of jogger in uphills is 4 mile per hour
And The speed of jogger in downhills is 10 mile per hour Answer
Answer:
±i
Step-by-step explanation:
Observing that the first two coefficients are the same as the last two, we can factor this function by grouping.
f(x) = (x^3 -7x^2) +(x -7) = x^2(x -7) +1(x -7)
f(x) = (x^2 +1)(x -7)
The factor x-7 has a real zero at x=7, so the complex zeros come from the quadratic factor (x^2 +1).
Setting that to zero and solving for x, we find ...
x^2 +1 = 0
x^2 = -1
x = ±√(-1) = ±i
The complex zeros are x = +i and x = -i.