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-BARSIC- [3]
3 years ago
6

How do you find the vertical asymptote of a rational expression?

Mathematics
1 answer:
ElenaW [278]3 years ago
5 0
Here is the answer to the question. Vertical asymptotes a<span>re vertical lines which correspond to the zeroes of the denominator of a </span>rational function. Therefore, in order to find the vertical asymptote of a rational expression, what you are going to do is to <span>set the denominator equal to 0 and solve for x. Hope this helps.</span>
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Can someone please help this is due tomorrow plz help I’m begging you btw ( I’m new to this app)
spin [16.1K]
Focus on the regression line. Notice how (0,90) and (1,75) are on this line. Compute the slope of the line through those points

Use the slope formula
m = (y2-y1)/(x2-x1)
m = (75-90)/(1-0)
m = -15/1
m = -15

So Matthew's balance is decreasing by approximately 15 dollars each month. The negative slope means "decrease". This is shown by the fact that the line goes downhill as you move from left to right.

Answer: decreases by $15 each month
7 0
4 years ago
If x varies directly with y and x=6 when y=8, find x when y=18.
andrey2020 [161]

Answer:

x = 13.5

Step-by-step explanation:

direct variation

y = kx

substitute x and y to find k

8 = k*6

divide by 6

8/6 =k

4/3 = k

y = 4/3 x

now put in y =18

18 = 4/3 x

 multiply by 3/4

18 * 3/4 = 3/4 * 4/3 x

54/4 = x

change to a decimal

13.5 =x


6 0
3 years ago
Which equation is in point-slope form for the given point and slope?
faust18 [17]

Answer: y-7 = 4(x+3), choice B

============================================

Point slope form is generally

y-y1 = m(x-x1)

we have m as the slope and (x1,y1) as the point this line goes through. In this case,

m = 4

(x1,y1) = (-3,7) so x1 = -3 and y1 = 7

So,

y-y1 = m(x-x1)

y - 7 = 4(x - (-3))

y - 7 = 4(x + 3)

which is why choice B is the answer

6 0
3 years ago
Read 2 more answers
Please help with my geometry homework!​
rusak2 [61]

Answer:

from that passage AB+BD=AD ; -4x+50+2x+4=2x+46 so -2x+54=2x+46 ; x=2.

AC=AB+BC ; AB=-4x+50=-4(2)+50=42

the total lengths is AD=2x+46=50

Therefore AC is more than 42 and less than 50 ; you can answer b,c,g

8 0
4 years ago
What is the exact distance from (−1, 4) to (6, −2)?
Studentka2010 [4]
Same as last time:

d^2=(x2-x1)^2+(y2-y1)^2

d^2=(6--1)^2+(-2-4)^2

d^2=7^2+(-6)^2

d^2=49+36

d^2=85

d=√85  (85=5*7 and both 5 and 7 are prime so √85 cannot be simplified any further)

The exact distance is √85 units.  
8 0
3 years ago
Read 2 more answers
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