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-BARSIC- [3]
3 years ago
6

How do you find the vertical asymptote of a rational expression?

Mathematics
1 answer:
ElenaW [278]3 years ago
5 0
Here is the answer to the question. Vertical asymptotes a<span>re vertical lines which correspond to the zeroes of the denominator of a </span>rational function. Therefore, in order to find the vertical asymptote of a rational expression, what you are going to do is to <span>set the denominator equal to 0 and solve for x. Hope this helps.</span>
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Can someone please help for brainlest
Klio2033 [76]

Answer:125√3:6

Step-by-step explanation:

5 0
3 years ago
Use mathematical induction to show that 4^n ≡ 3n+1 (mod 9) for all n equal to or greater than 0
cestrela7 [59]
When n=0, you have

4^0=1\equiv3(0)+1=1\mod9

Now assume this is true for n=k, i.e.

4^k\equiv3k+1\mod9

and under this hypothesis show that it's also true for n=k+1. You have

4^k\equiv3k+1\mod9
4\equiv4\mod9
\implies 4\times4^k\equiv4(3k+1)\mod9
\implies 4^{k+1}\equiv12k+4\mod9

In other words, there exists M such that

4^{k+1}=9M+12k+4

Rewriting, you have

4^{k+1}=9M+9k+3k+4
4^{k+1}=9(M+k)+3k+3+1
4^{k+1}=9(M+k)+3(k+1)+1

and this is equivalent to 3(k+1)+1 modulo 9, as desired.

3 0
3 years ago
Can someone find the slope
Alex787 [66]
Hello!

The slope is in rise over run form

From point to point to goes up 4 and over 10

that is 4/10

This can be simplified to 2/5

The answer is 2/5

Hope this helps!
4 0
3 years ago
Read 2 more answers
Please help me guys I am in trouble​
777dan777 [17]
The answer to the question ought to be 10
5 0
2 years ago
A number is 6 units away from -3 on the number line. Which of the following could the number be? Select all that apply.
Murljashka [212]
Answer is 3, -9


6 units away means x+6 or x-6
-3+6=3 (you can draw a number line if it helps you)
Or -3-6=-9
Therefore answer is both 3 and -9
4 0
2 years ago
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