Answer:
Area of the wall to be painted = (11x² + 12x) square units
Step-by-step explanation:
The figure that should be attached to this question is missing. The figure was obtained and is attached to this solution provided.
From the image attached, it is given that the dimension of the rectangular wall to be painted is (4x+3) by (4x), the dimensions of the window is (2x) by (x) and the dimensions of the door is (x) by (3x).
Since, the window space and the door space cannot be painted along with the wall, the Area of the rectangular wall that will be painted will be given by the expression
(Total Area of the rectangular wall) - [(Area of window space) + (Area of door space)]
Area of a rectangular figure = Length × Breadth
Total area of rectangular wall = (4x+3) × 4x = (16x² + 12x) square units
Area of window space = (2x) × (x) = (2x²) square units
Area of door space = (x) × (3x) = (3x²) square units
Area of the wall to be painted = (16x² + 12x) - (2x² + 3x²)
= 16x² + 12x - 5x²
= (11x² + 12x) square units
Hope this Helps!!!
Answer:
idk for sure but id say 10x
Step-by-step explanation:
Answer:
−3x > 24
Step-by-step explanation:
Adding 10 to both sides of the inequality will give the missing step:
-3x -10 +10 > 14 +10
-3x > 24
Answer:
h = 6 cm
Step-by-step explanation:
Given that,
The area of a trapezoid, A = 66 cm²
The sum of the lengths of the two bases of a trapezoid is 22 cm.
We need to find the height of the trapezoid.
The area of a trapezium is given by :
![A=\dfrac{1}{2}\times (\text{sum of parallel sides})\times \text{height}](https://tex.z-dn.net/?f=A%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%20%28%5Ctext%7Bsum%20of%20parallel%20sides%7D%29%5Ctimes%20%5Ctext%7Bheight%7D)
Substitute the values,
![h=\dfrac{2A}{\text{sum of parallel sides}}\\\\h=\dfrac{2\times 66}{22}\\\\h=6\ cm](https://tex.z-dn.net/?f=h%3D%5Cdfrac%7B2A%7D%7B%5Ctext%7Bsum%20of%20parallel%20sides%7D%7D%5C%5C%5C%5Ch%3D%5Cdfrac%7B2%5Ctimes%2066%7D%7B22%7D%5C%5C%5C%5Ch%3D6%5C%20cm)
So, the height of the trapezoid 6 cm.
It’s around 45 degrees I think
I hope I helped : )