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Semenov [28]
3 years ago
13

3(7 + x2); x = 2 (x is squared by 2) ( evaluate each expression for the given values of the variables)

Mathematics
1 answer:
dedylja [7]3 years ago
8 0

Answer:

33

Step-by-step explanation:

This is a substitution question,so to solve you will have to substitute... substitution question is when a specific number is given replace a certain number

Back to the question,3(7+x2)

And x is given to be 2

So let's continue by substituting the value of x into the equation

3(7+2^2)

3(7+4)

3(11)

33

The final answer is 33

Hope you understand how we get our final answer,just follow the step above

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Add 6 to the quotient of j and k
BARSIC [14]

Answer:

     j/k + 6

Step-by-step explanation:

Add 6 to the quotient of j and k comes out to:

                                  j/k + 6

4 0
3 years ago
The high school graduating class of 2010 was 260 people. Five years later the high school graduating class was 320 people. By ap
jeka94

Answer:

The high school graduating class changed by approximately 23%

Step-by-step explanation:

we have

The high school graduating class of 2010 was 260 people

Five years later the high school graduating class was 320 people.

we know that

260 people represent the 100%

so

The difference is (320-260)=60 people

using proportion

Find out what percentage represent 60 people

Let

x ----> the percentage that represent 60 people

\frac{260}{100\%}=\frac{60}{x}\\\\x= 100\%(60)/260\\\\x=23.1\%

therefore

The high school graduating class changed by approximately 23%

3 0
3 years ago
EASY PLS HELP ASAP!!<br> ANY QUESTION PLSSS
Lena [83]
Rudy’s age today is 96.
5 0
3 years ago
How many students must be randomly selected to estimate the mean weekly earnings of students at one college? We want 95% confide
kari74 [83]

Answer:

The sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

CI=\bar x\pm z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

The margin of error of a (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

MOE=z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

The information provided is:

<em>σ</em> = $60

<em>MOE</em> = $2

The critical value of <em>z</em> for 95% confidence level is:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

Compute the sample size as follows:

MOE=z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

       n=[\frac{z_{\alpha/2}\times \sigma }{MOE}]^{2}

          =[\frac{1.96\times 60}{2}]^{2}

          =3457.44\\\approx 3458

Thus, the sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.

8 0
3 years ago
(2a-4a2+8)+(5a2 -5a+6)
lana [24]
A^2-3a+14 is the answer :)
8 0
2 years ago
Read 2 more answers
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