I think the answer would be -2.5 because 0-5=-5 and 4-2=2 you subtract the perfect points X1-x2 with y2-y1
The scale for the second values is 56/8 = 7
C = 3 x 7 = 21
C= 21
You can subtract 9 from the 713 value and trace until you get a multiple of 7 or vice versa.
It could be one of :
80 figilbuttons and 7 rybirens
or
14 rybirens and 73 figilbuttons
Four hundreds two tens and three ones
The parentheses must be placed here 48 - (5 + 2) * 3 + 6 in order for the equation to equal 33.