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Marizza181 [45]

3 years ago

5

Jackson deposited $5,000 at 3.8% interest, compounded continuously, when he was 18 years old. How much will be in the account wh

en he is 40 years old if he made no other deposits or withdrawals?

1 answer:

Ivahew [28]3 years ago

6 0

5,000 × 3.8%= 19,000×18= 342,000 × 40 = 13,680,000

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3 years ago

The 6% state income tax on a 42'000 salery

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Answer:

well, simply, it would be $2520.

in reality, an income tax does not work that simply. income taxes are figured using brackets, where (just making up numbers) the first $15000 might be taxed at 2%, earnings between $15,001 to $30,000 are taxed at 4%, and so on.

Thus, without knowing the tax tables to know the different rates and brackets, it's impossible to give an answer.

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42000×.06= 2520

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2 years ago

What is the positive slope of the asymptote of (y+11)^2/100-(x-6)^2/4=1? The positive slope of the asymptote is .

VladimirAG [237]

Answer:

the positive slope of the asymptote = 5

Step-by-step explanation:

Given that:

$\frac{(y+11)^2}{100} -\frac{(x-6)^2}{4} =1$

Using the standard form of the equation:

$\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}= 1$

where:

(h,k) are the center of the hyperbola.

and the y term is in front of the x term indicating that the hyperbola opens up and down.

a = distance that indicates how far above and below of the center the vertices of the hyperbola are.

For the above standard equation; the equation for the asymptote is:

$y = \pm \frac{a}{b} (x-h)+k$

where;

$\frac{a}{b}$ is the slope

From above;

(h,k) = 11, 100

$a^2$ = 100

a = $\sqrt{100}$

a = 10

$b^2 =4$

b = $\sqrt{4}$

b = 2

$y = \pm \frac{10}{2} (x-11)+2$

$y = \pm 5 (x-11)+2$

y = 5x-53 , -5x -57

Since we are to find the positive slope of the asymptote: we have

$\frac{a}{b}$ to be the slope in the equation $y = \pm \frac{10}{2} (y-11)+2$

$\frac{a}{b}$ = $\frac{10}{2}$

$\frac{a}{b}$ = 5

Thus, the positive slope of the asymptote = 5

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2 years ago

What is 14 x 72 equal

irina1246 [14]

Answer:

$1008$

Step-by-step explanation:

When you multiply, always start on the first value. In this case, this would be 2 from 72.

$2 * 4$

$==> 8[tex]and[tex]2 * 1$

$2$

Write now, you should have 82 as your first value.

Now for your second value, which would be 7. But first you need to add a zero, because you are doing the tens place.

$7 * 4$

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<u>Now you put the two over your next equation:</u>

and

$7 * 1$

$==> 7$

$+1$

$==> 9$

Now you should have 980 written.

<u>Now add your two numbers together:</u>

<u></u>

$82 + 980$

$==> 1008$

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3 years ago

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