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2 years ago

The radius of a circular box is 21 centimeters. What is the circumference of the box? A 66cm B 132cm C 176cm D 1386cm

Mathematics

1 answer:

Ulleksa [173]2 years ago

8 0

The answer would be 132 because the formula for find circumference while using radius is 2(3.14)r .

C= 2(3.13)21

C= 6.28 • 21 = 131.88

131.88 rounded is 132

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How do u solve 6 1/2 - 1 9/10

pishuonlain [190]

Just convert the fractions into decimals. for example, 6 1/2 equals 6.5 as a decimal. 1 9/10 would be converted to 1.9. Then just do 6.5-1.9, and that equals 4.6.

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3 years ago

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A building 50 ft high casts a 75-ft shadow. Sarah casts a 6-ft shadow. The triangle formed by the building and its shadow is sim

Rom4ik [11]

Make each known side into a ratio like so...
75/6
(Because 75 is the shadow casted by the building, and 6 is the shadow casted by sarah)
and 50/x
(50 is how tall the building is and sarah's height is what needs to be found)
Therefore,
75 50
---- -----
6 x

Do cross products;
50 x 6 = 75 x X
300 = 75x
Divide by 75
x = 4ft

8 0

3 years ago

The question is in the picture.

dangina [55]

Let's denote no of seats in first row with r1 , second row with r2.....and so on.

r1=5

Since next row will have 10 additional row each time when we move to next row,

So,

r2=5+10=15

r3=15+10=25

Using the terms r1,r2 and r3 , we can find explicit formula

r1=5=5+0=5+0×10=5+(1-1)×10

r2=15=5+10=5+(2-1)×10

r3=25=5+20=5+(3-1)×10

So for nth row,

rn=5+(n-1)×10

Since 5=r1 and 10=common difference (d)

rn=r1+(n-1)d

Since 'a' is a convention term for 1st term,

which is an explicit formula to find no of seats in any given row.

Using above explicit formula, we can calculate no of seats in 7th row,

r7=5+(7-1)×10

r7=5+(7-1)×10 =5+6×10

r7=5+(7-1)×10 =5+6×10 =65

which is the no of seats in 7th row.

8 0

3 years ago

(05.03)(picture included)Sue has to cut her grandma's grass this weekend and wants to know exactly how much area she will be cut

kifflom [539]

Answer:

Solution given:

BD=35ft

AC=43ft

AB=8ft

EF=33-8=25ft

AE=26ft

Now

area of right angled triangle ∆AEF

=½(EF*AE)=½(25×25)=312.5ft²

area of parallel trapezoid=½AB(BD+AC)

=½*8(35+43)=312ft²

So

Area of polygon : 312.5+312=624.5ft² is a required answer.

3 0

2 years ago

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Write an equation for a line that is parallel to 2x+5y=15 and passes through the point (-10, 3)

Lyrx [107]

Answer:

The equation of the line is,

$y = - \frac{2}{5} x - 1$

Step-by-step explanation:

First, you have to write it in a form of y = mx + b :

$2x + 5y = 15$

$5y = 15 - 2x$

$y = 3 - \frac{2}{5} x$

$y = - \frac{2}{3} x + 5$

When both lines are parallel to each other, they will have to same gradient value. So the equation of the line is y = (-2/5)x + b. Next, you have to find the value of b by substutituting (-10,3) into the equation :

$y = - \frac{ 2}{5}x + b$

$let \: x = - 10,y = 3$

$3 = - \frac{2}{5} ( - 10) + b$

$3 = 4 + b$

$3 - 4 = b$

$b = - 1$

3 0

3 years ago

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