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andrezito [222]
2 years ago
12

WHat is the answer for the blank boxes ig?

Mathematics
2 answers:
tatuchka [14]2 years ago
4 0
3/8 equals 0.375 as a decimal number and as a percentage it equals 37.5%. I just divided 3 by 8 and multiplied by one hundred.
Andrej [43]2 years ago
3 0
It would be 0.375 and 37.5%
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38 kg of onions cost $144.40. how much would 49 kg cost?
Lerok [7]

Answer:

$186.2

Step-by-step explanation:

   38 kg costs $144.40

∴ 1 kg costs = \frac{144.40}{38}  = $3.8

   49 kg costs = 3.8  x  49

                        = $186.2

7 0
1 year ago
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in a survey 2,000 people who owned a certain type of car, 1,100 said they would buy that type of car again what percent of peopl
Gnom [1K]
The answer is 55% because 1,100 is 55% of 2,000
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3 years ago
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6) A climber is on a hike. After 2 hours she is at an altitude of 400 feet. After 6 hours, she is at an
Bas_tet [7]

Answer:

<em>Her rate of change is 75 ft/h</em>

Step-by-step explanation:

<u>Rate of Change</u>

It measures how one quantity varies with respect to another. The second variable usually is the time.

The climber is hiking. We are given two points of her progress: At 2 hours, she is at 400 ft. This corresponds to the point (2,400).

At 6 hours, she is at 700 ft. This is the point (6,700)

The rate of change is the slope between these two points or the quotient of the variations of each variable:

\displaystyle m=\frac{700\ ft-400\ ft}{6\ h-2\ h}

\displaystyle m=\frac{300\ ft}{4\ h}

m=75\ ft/h

Her rate of change is 75 ft/h

3 0
3 years ago
Erin has 5 cans of juice and drinks 1/3 of a can daily. in how many days will she empty all the cans she has? I think it's 1/15
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The correct answer to your question is 15 days because if she drinks 1/3 of a can a day it will take 3 days to drink one can. Now multiple the 3 days for one can by the 5 cans and you get 15 days to finish all of the cans.
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2 years ago
Carrie had 140 coins.She has 10 times as many coins as she had last month.How many coins did Carrie have last month?
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Carrie had 14 coins last month
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3 years ago
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