For any equation,
assume solution of a form, 
Which leads to,
Simplify to,
Then find solutions,
For non repeated real root y, we have a form of,
Following up,
For two non repeated complex roots 
where,
and,
the general solution has a form of,
Or in this case,
Now we just refine and get,
Hope this helps.
r3t40
Answer:
-23, 5
Step-by-step explanation:
JK = 14 and K = -9
J could be on the left or the right of -9
Add 14 to -9
14+-9 = 5
So J could be at 5
Subtract 14 from -9
-14-9 = -23
The answer is c because 8 - 5 is 3.
Answer:
See below
Step-by-step explanation:
Remember the notation and rules of quantifiers. ∀ is the universal quantifier and ∃ is the existential quantifier. To negate ∀x p(x) , write ∃x ¬p(x). To negate ∃x p(x) , write ∀x ¬p(x)
Part I:
A) None of life's problems have a simple solution.
B) All of life's problems have a simple solution.
C) Some of life's problems have a simple solution
D) All of life's problems have a simple solution (notice how the original statements in B and D mean exactly the same)
E) Some of life's problems do not have a simple solution.
Part II: Let x be a variable representing one of life's problems, y be a variable representing solutions, p(x):="x has a simple solution", and q(x,y):="y is a simple solution of x".
A) (∀x)(¬p(x)) or ¬(∃x)(p(x))
B) (∀x)(∃y)(q(x,y))
C) (∃y)(∀x)(q(x,y)). Note that the order of quantifiers is important. B) and C) have different meanings. In C) there is an universal solution of all problems, in B) each problem has its solution.
D) (∀x)(p(x))
E) Same as C)
