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ella [17]
3 years ago
7

What is 3 to the power of 3

Mathematics
2 answers:
S_A_V [24]3 years ago
7 0
It is 27 because 3*3=9 and 9*3= 27.
shutvik [7]3 years ago
4 0
Your answer would be 27
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I need help thank you.
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The answers and steps are in the picture

6 0
2 years ago
Select the correct answer.<br> What is 22% of 50?<br> Α.44<br> B.28<br> C.22<br> D. 11
Damm [24]
The answer should be D. 11?
7 0
2 years ago
Read 2 more answers
There is anyone who r from India​
nataly862011 [7]

Answer:i dont think so

Step-by-step explanation:

7 0
3 years ago
How to solve logarithmic equations as such
Serga [27]

\bf \textit{exponential form of a logarithm} \\\\ \log_a b=y \implies a^y= b\qquad\qquad a^y= b\implies \log_a b=y \\\\\\ \begin{array}{llll} \textit{Logarithm of exponentials} \\\\ \log_a\left( x^b \right)\implies b\cdot \log_a(x) \end{array} ~\hspace{7em} \begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{\textit{we'll use this one}}{a^{log_a x}=x} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \log_2(x-1)=\log_8(x^3-2x^2-2x+5) \\\\\\ \log_2(x-1)=\log_{2^3}(x^3-2x^2-2x+5) \\\\\\ \log_{2^3}(x^3-2x^2-2x+5)=\log_2(x-1) \\\\\\ \stackrel{\textit{writing this in exponential notation}}{(2^3)^{\log_2(x-1)}=x^3-2x^2-2x+5}\implies (2)^{3\log_2(x-1)}=x^3-2x^2-2x+5

\bf (2)^{\log_2[(x-1)^3]}=x^3-2x^2-2x+5\implies \stackrel{\textit{using the cancellation rule}}{(x-1)^3=x^3-2x^2-2x+5} \\\\\\ \stackrel{\textit{expanding the left-side}}{x^3-3x^2+3x-1}=x^3-2x^2-2x+5\implies 0=x^2-5x+6 \\\\\\ 0=(x-3)(x-2)\implies x= \begin{cases} 3\\ 2 \end{cases}

5 0
3 years ago
The cost to purchase x tickets for an amusement park is represented by the equations y-50x+3.75. how much would it cost to purch
emmainna [20.7K]
I'm assuming that subtraction sign is mean to be an equals sign. If that is true than the answer is 403.75. 
4 0
3 years ago
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