Can someone help me with these to please I’m kinda stuck on them lol
1 answer:
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Answer:
(a) k'(0) = f'(0)g(0) + f(0)g'(0)
(b) m'(5) =
Step-by-step explanation:
(a) Since k(x) is a function of two functions f(x) and g(x) [ k(x)=f(x)g(x) ], so for differentiating k(x) we need to use <u>product rule</u>,i.e.,
this will give <em>k'(x)=f'(x)g(x) + f(x)g'(x)</em>
on substituting the value x=0, we will get the value of k'(0)
{for expressing the value in terms of numbers first we need to know the value of f(0), g(0), f'(0) and g'(0) in terms of numbers}{If f(0)=0 and g(0)=0, and f'(0) and g'(0) exists then k'(0)=0}
(b) m(x) is a function of two functions f(x) and g(x) [ ]. Since m(x) has a function g(x) in the denominator so we need to use <u>division rule</u> to differentiate m(x). Division rule is as follows :
this will give <em></em>
on substituting the value x=5, we will get the value of m'(5).
{for expressing the value in terms of numbers first we need to know the value of f(5), g(5), f'(5) and g'(5) in terms of numbers}
{NOTE : in m(x), g(x) ≠ 0 for all x in domain to make m(x) defined and even m'(x) }
{ NOTE : }
Answer:
C. The 6th term is positive/negative 80
Step-by-step explanation:
Given
Geometric Progression
Required
To get the 6th term of the progression, first we need to solve for the first term and the common ratio of the progression;
To solve the common ratio;
Divide the 7th term by the 5th term; This gives
Divide the numerator and the denominator of the fraction by 40
----- equation 1
Recall that the formula of a GP is
Where n is the nth term
So,
Substitute the above expression in equation 1
becomes
Square root both sides
r = ±
Next, is to solve for the first term;
Using
By substituting 160 for T5 and ± for r;
We get
Multiply through by 16
Now, we can easily solve for the 6th term
Recall that the formula of a GP is
Here, n = 6;
r = ±
So,
or
or
or
±80
Hence, the 6th term is positive/negative 80