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LuckyWell [14K]

3 years ago

10

There are 700 people at a funfair.

2 answers:

qwelly [4]3 years ago

5 0

Answer:

Answer is in Picture. Explanation as well

Eddi Din [679]3 years ago

5 0

700/7 = 100
100 * 4 = 400
There are 400 people are boys.

700/10 = 70

400 + 70 = 470
700 - 470 = 230
There are 230 adults at the funfair.

I hope I helped. I appreciate Brainliest

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$p = 0.1260$ --- p value

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Step-by-step explanation:

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$n_2 = 70$ $\bar x_2 = 106$ $\sigma_2 = 7.6$

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$H_a: \mu_1 - \mu_2 \ne 0$ ---- Alternate hypothesis

$\alpha = 0.05$

Solving (a): The test statistic

This is calculated as:

$z = \frac{\bar x_1 - \bar x_2}{\sqrt{\frac{\sigma_1^2}{n_1} + \frac{\sigma_2^2}{n_2} }}$

So, we have:

$z = \frac{104 - 106}{\sqrt{\frac{8.4^2}{80} + \frac{7.6^2}{70} }}$

$z = \frac{104 - 106}{\sqrt{\frac{70.56}{80} + \frac{57.76}{70}}}$

$z = \frac{-2}{\sqrt{0.8820 + 0.8251}}$

$z = \frac{-2}{\sqrt{1.7071}}$

$z = \frac{-2}{1.3066}$

$z = -1.53$

Solving (b): The p value

This is calculated as:

$p = 2 * P(Z < z)$

So, we have:

$p = 2 * P(Z < -1.53)$

Look up the z probability in the z score table. So, the expression becomes

$p = 2 * 0.0630$

$p = 0.1260$

Solving (c): With $\alpha = 0.05$ , what is the conclusion based on the p value

We have:

$\alpha = 0.05$

In (b), we have:

$p = 0.1260$

By comparison:

$p > \alpha$

i.e.

$0.1260 > 0.05$

So, we fail to reject the null hypothesis.

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