Percent cost of the total spent on
each equipment = 14.23%,fees=62.45% and transportation = 23.32%.
As given in the question,
Money spent on
Each equipment = $36
Fees = $158
Transportation = $59
Total money spent = $( 36 + 158 + 59)
= $253
Percent cost of the total spent on
Each equipment = (36/253) × 100
= 14.23%
Fees = (36/253) × 100
= 62.45%
Transportation =(36/253) × 100
= 23.32%
Therefore, percent cost of the total spent on
each equipment = 14.23%,fees=62.45% and transportation = 23.32%.
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we know that
The measure of the external angle is the semidifference of the arcs that it covers
so
∠MLN=(1/2)*(mayor arc MN-minor arc MN)
Let
x------> minor arc MN
major arc MN=360-x
substitute in the formula above
∠MLN=(1/2)*(mayor arc MN-minor arc MN)
75.86=(1/2)*(360-x-x)------> 151.72=(360-2x)------>360-151.72=2x
x=104.14°
therefore
the answer is
the measure of arc MN (minor arc) is 104.14°
Answer:
(a + b + c)/2
Step-by-step explanation:
Number of kids in first class: a
Number of kids in second class: b
Number of kids in third class: c
The total number of kids in all classes is: a + b + c
The total number of kids is divided equally between 2 buses:
(a + b + c)/2
y=6x-14
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Answer:
y = 2.5x + 33.4, y = 75.9 miles
Step-by-step explanation:
Equation is y = 2.5x + 33.4
17 = 2.5 x + 33.4
y = 2.5 (17) + 33.4
y = 42.5 + 33.4
y = 75.9 miles
