Right angle is the answer I think ( not sure though )
Answer:
I am pretty sure this statement is false so it'd be: x= 0
Step-by-step explanation:
Consider all options:
A.
![\left[\begin{array}{cc}5&5\\-4&-4\end{array}\right] \cdot \left[\begin{array}{cc}5&5\\-4&-4\end{array}\right] =\left[\begin{array}{cc}5\cdot 5+5\cdot (-4)&5\cdot 5+5\cdot (-4)\\-4\cdot 5+(-4)\cdot (-4)&-4\cdot 5+(-4)\cdot (-4)\end{array}\right]=](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D5%265%5C%5C-4%26-4%5Cend%7Barray%7D%5Cright%5D%20%5Ccdot%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D5%265%5C%5C-4%26-4%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D5%5Ccdot%205%2B5%5Ccdot%20%28-4%29%265%5Ccdot%205%2B5%5Ccdot%20%28-4%29%5C%5C-4%5Ccdot%205%2B%28-4%29%5Ccdot%20%28-4%29%26-4%5Ccdot%205%2B%28-4%29%5Ccdot%20%28-4%29%5Cend%7Barray%7D%5Cright%5D%3D)
![=\left[\begin{array}{cc}5&5\\-4&-4\end{array}\right].](https://tex.z-dn.net/?f=%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D5%265%5C%5C-4%26-4%5Cend%7Barray%7D%5Cright%5D.)
This option is true.
B.
![\left[\begin{array}{cc}6&5\\5&6\end{array}\right] \cdot \left[\begin{array}{cc}6&5\\5&6\end{array}\right] =\left[\begin{array}{cc}6\cdot 6+5\cdot 5&6\cdot 5+5\cdot 6\\5\cdot 6+6\cdot 5&5\cdot 5+6\cdot 6\end{array}\right]=](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D6%265%5C%5C5%266%5Cend%7Barray%7D%5Cright%5D%20%5Ccdot%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D6%265%5C%5C5%266%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D6%5Ccdot%206%2B5%5Ccdot%205%266%5Ccdot%205%2B5%5Ccdot%206%5C%5C5%5Ccdot%206%2B6%5Ccdot%205%265%5Ccdot%205%2B6%5Ccdot%206%5Cend%7Barray%7D%5Cright%5D%3D)
![=\left[\begin{array}{cc}61&60\\60&61\end{array}\right].](https://tex.z-dn.net/?f=%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D61%2660%5C%5C60%2661%5Cend%7Barray%7D%5Cright%5D.)
This option is false.
C.
![\left[\begin{array}{cc}0.5&-0.5\\-0.5&0.5\end{array}\right] \cdot \left[\begin{array}{cc}0.5&-0.5\\-0.5&0.5\end{array}\right] =\left[\begin{array}{cc}0.5\cdot 0.5+(-0.5)\cdot (-0.5)&0.5\cdot (-0.5)+(-0.5)\cdot 0.5\\-0.5\cdot 0.5+0.5\cdot (-0.5)&-0.5\cdot (-0.5)+0.5\cdot 0.5\end{array}\right]=](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D0.5%26-0.5%5C%5C-0.5%260.5%5Cend%7Barray%7D%5Cright%5D%20%5Ccdot%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D0.5%26-0.5%5C%5C-0.5%260.5%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D0.5%5Ccdot%200.5%2B%28-0.5%29%5Ccdot%20%28-0.5%29%260.5%5Ccdot%20%28-0.5%29%2B%28-0.5%29%5Ccdot%200.5%5C%5C-0.5%5Ccdot%200.5%2B0.5%5Ccdot%20%28-0.5%29%26-0.5%5Ccdot%20%28-0.5%29%2B0.5%5Ccdot%200.5%5Cend%7Barray%7D%5Cright%5D%3D)
![=\left[\begin{array}{cc}0.5&-0.5\\-0.5&0.5\end{array}\right].](https://tex.z-dn.net/?f=%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D0.5%26-0.5%5C%5C-0.5%260.5%5Cend%7Barray%7D%5Cright%5D.)
This option is true.
D.
![\left[\begin{array}{cc}0.5&0.5\\-0.5&0.5\end{array}\right] \cdot \left[\begin{array}{cc}0.5&0.5\\-0.5&0.5\end{array}\right] =\left[\begin{array}{cc}0.5\cdot 0.5+0.5\cdot (-0.5)&0.5\cdot 0.5+0.5\cdot 0.5\\-0.5\cdot 0.5+0.5\cdot (-0.5)&-0.5\cdot 0.5+0.5\cdot 0.5\end{array}\right]=](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D0.5%260.5%5C%5C-0.5%260.5%5Cend%7Barray%7D%5Cright%5D%20%5Ccdot%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D0.5%260.5%5C%5C-0.5%260.5%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D0.5%5Ccdot%200.5%2B0.5%5Ccdot%20%28-0.5%29%260.5%5Ccdot%200.5%2B0.5%5Ccdot%200.5%5C%5C-0.5%5Ccdot%200.5%2B0.5%5Ccdot%20%28-0.5%29%26-0.5%5Ccdot%200.5%2B0.5%5Ccdot%200.5%5Cend%7Barray%7D%5Cright%5D%3D)
![=\left[\begin{array}{cc}0&0.5\\-0.5&0\end{array}\right].](https://tex.z-dn.net/?f=%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D0%260.5%5C%5C-0.5%260%5Cend%7Barray%7D%5Cright%5D.)
This option is false.
E.
![\left[\begin{array}{cc}-6&-6\\5&5\end{array}\right] \cdot \left[\begin{array}{cc}-6&-6\\5&5\end{array}\right] =\left[\begin{array}{cc}-6\cdot (-6)+(-6)\cdot 5&-6\cdot (-6)+(-6)\cdot 5\\5\cdot (-6)+5\cdot 5&5\cdot (-6)+5\cdot 5\end{array}\right]=](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-6%26-6%5C%5C5%265%5Cend%7Barray%7D%5Cright%5D%20%5Ccdot%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-6%26-6%5C%5C5%265%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-6%5Ccdot%20%28-6%29%2B%28-6%29%5Ccdot%205%26-6%5Ccdot%20%28-6%29%2B%28-6%29%5Ccdot%205%5C%5C5%5Ccdot%20%28-6%29%2B5%5Ccdot%205%265%5Ccdot%20%28-6%29%2B5%5Ccdot%205%5Cend%7Barray%7D%5Cright%5D%3D)
![=\left[\begin{array}{cc}6&6\\-5&-5\end{array}\right].](https://tex.z-dn.net/?f=%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D6%266%5C%5C-5%26-5%5Cend%7Barray%7D%5Cright%5D.)
This option is false.
Answer: correct options are A and C.
Yes, Torri does have enough.
How to find the answer:
Find the decimal of 7% which is 0.07
Multiply 0.07 times $18 which gives you 1.26
0.07 x 18 = 1.26
Add 1.26 to 18 which gives us 19.26
1.26 + 18 = 19.26
Our finale answer is 19.26
Torri has enough money to buy her dad the DVD.
Hope this helps! =)
Answer:
There is enough not evident to support dealer's claim that his sales is no more than $80.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = $80
Sample mean,
= $91
Sample size, n = 20
Alpha, α = 0.05
Sample standard deviation, s = $21
First, we design the null and the alternate hypothesis
We use one-tailed t test to perform this hypothesis.
Formula:

Putting all the values, we have

Now,
Since,
The calculated test statistic is greater than the critical value, we fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.
Conclusion:
There is enough not evident to support dealer's claim that his sales is no more than $80.