Answer:
x = 18
Step-by-step explanation:
Given
3 +
= 
Multiply through by the LCM of 2 and 3 to clear the fractions.
The LCM of 2 and 3 is 6, thus
18 + 2x = 3x ( subtract 2x from both sides )
18 = x
Answer:
0.9256
Step-by-step explanation:
Given that a convenience store owner claims that 55% of the people buying from her store, on a certain day of the week, buy coffee during their visit
Let X be the number of customers who buy from her store, on a certain day of the week, buy coffee during their visit
X is Binomial (35, 0.55)
since each customer is independent of the other and there are two outcomes.
By approximation to normal we find that both np and nq are >5.
So X can be approximated to normal with mean = np = 19.25
and std dev = 
Required probability = prob that fewer than 24 customers in the sample buy coffee during their visit on that certain day of the week
=
(after effecting continuity correction)
= 0.9256
Answer:
We accept H₀ we don´t have enough evidence to support that the mean thickness is greater than 41 mm
Step-by-step explanation:
Sample Information:
Results:
41.8
40.9
42.1
41.2
40.5
41.1
42.6
40.6
From the table we get:
sample mean : x = 41.35
sample standard deviation s = 0.698
Hypothesis Test:
Null Hypothesis H₀ x = 41
Alternative Hypothesis Hₐ x > 41
The test is a one-tail test
If significance level is 0.01 and n = 8 we need to use t-student distribution
From t-table α = 0.01 and degree of freedom df = n - 1 df = 8 - 1
df = 7 t(c) = 2.998
To calculate t(s) = ( x - 41 ) / s/√n
t(s) = ( 41.35 - 41 ) / 0.698/√8
t(s) = 0.35 * 2.83/ 0.698
t(s) = 1.419
Comparing t(s) and t(c)
t(s) < t(c)
t(s) is in the acceptance region we accept H₀
Answer:
See explanation
Step-by-step explanation:
William has 24 cans of fruit and 60 cans of vegetables that he will be putting into bags for a food drive.
Factor number 24 and 60:

Find the greatest common factor

Hence, the greatest number of bags William can make is 12.
Each of these bags will have
cans of fruit and
cans of vegetables.
If he made fewer bags, 6 bags, each of these bags will have
cans of fruit and
cans of vegetables.
If he made fewer bags, 4 bags, each of these bags will have
cans of fruit and
cans of vegetables.
If he made fewer bags, 3 bags, each of these bags will have
cans of fruit and
cans of vegetables.
If he made fewer bags, 2 bags, each of these bags will have
cans of fruit and
cans of vegetables.