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3 years ago

Pls help me on this!

Mathematics

1 answer:

Ira Lisetskai [31]3 years ago

3 0

Answer:

5 2/3

Step-by-step explanation:

So because it is a mixed number that means you want to have a whole plus a fraction. You keep the 5 as the whole and because 2/3=.666666. You add them together making 5 2/3.

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3+x/3=x/2<br> answer and the steps please

AveGali [126]

Answer:

x = 18

Step-by-step explanation:

Given

3 + $\frac{x}{3}$ = $\frac{x}{2}$

Multiply through by the LCM of 2 and 3 to clear the fractions.

The LCM of 2 and 3 is 6, thus

18 + 2x = 3x ( subtract 2x from both sides )

18 = x

3 0

2 years ago

\begin{aligned} 4{,}570=& 4 \text{ thousands} + 5 \text{ hundreds} + 7 \text{ tens} \\\\ 4{,}570=& 3 \text{ thousands} +

iris [78.8K]

What’s the question ?

3 0

3 years ago

Use the appropriate normal distribution to approximate the resulting binomial distributions. A convenience store owner claims th

Naddika [18.5K]

Answer:

0.9256

Step-by-step explanation:

Given that a convenience store owner claims that 55% of the people buying from her store, on a certain day of the week, buy coffee during their visit

Let X be the number of customers who buy from her store, on a certain day of the week, buy coffee during their visit

X is Binomial (35, 0.55)

since each customer is independent of the other and there are two outcomes.

By approximation to normal we find that both np and nq are >5.

So X can be approximated to normal with mean = np = 19.25

and std dev = $\sqrt{npq} \\=2.943$

Required probability = prob that fewer than 24 customers in the sample buy coffee during their visit on that certain day of the week

= $P(X$ (after effecting continuity correction)

= 0.9256

6 0

2 years ago

The thickness of eight pads designed for use in aircraft engine mounts are measured. The results, in mm, are 41.8, 40.9, 42.1, 4

nika2105 [10]

Answer:

We accept H₀ we don´t have enough evidence to support that the mean thickness is greater than 41 mm

Step-by-step explanation:

Sample Information:

Results:

41.8

40.9

42.1

41.2

40.5

41.1

42.6

40.6

From the table we get:

sample mean : x = 41.35

sample standard deviation s = 0.698

Hypothesis Test:

Null Hypothesis H₀ x = 41

Alternative Hypothesis Hₐ x > 41

The test is a one-tail test

If significance level is 0.01 and n = 8 we need to use t-student distribution

From t-table α = 0.01 and degree of freedom df = n - 1 df = 8 - 1

df = 7 t(c) = 2.998

To calculate t(s) = ( x - 41 ) / s/√n

t(s) = ( 41.35 - 41 ) / 0.698/√8

t(s) = 0.35 * 2.83/ 0.698

t(s) = 1.419

Comparing t(s) and t(c)

t(s) < t(c)

t(s) is in the acceptance region we accept H₀

7 0

3 years ago

William has 24 cans of fruit and 60 cans of vegetables that he will be putting into bags for a food drive. He wants each bag to

nataly862011 [7]

Answer:

See explanation

Step-by-step explanation:

William has 24 cans of fruit and 60 cans of vegetables that he will be putting into bags for a food drive.

Factor number 24 and 60:

$24=2\cdot 12=2\cdot 2\cdot 6=2\cdot 2\cdot 2\cdot 3=2^3\cdot 3\\ \\60=2\cdot 30=2\cdot 2\cdot 15=2\cdot 2\cdot 3\cdot 5=2^2\cdot 3\cdot 5$

Find the greatest common factor

$GCF(24,60)=2^2\cdot 3=12$

Hence, the greatest number of bags William can make is 12.

Each of these bags will have $24\div 12=2$ cans of fruit and $60\div 12=5$ cans of vegetables.

If he made fewer bags, 6 bags, each of these bags will have $24\div 6=4$ cans of fruit and $60\div 6=10$ cans of vegetables.

If he made fewer bags, 4 bags, each of these bags will have $24\div 4=6$ cans of fruit and $60\div 4=15$ cans of vegetables.

If he made fewer bags, 3 bags, each of these bags will have $24\div 3=8$ cans of fruit and $60\div 3=20$ cans of vegetables.

If he made fewer bags, 2 bags, each of these bags will have $24\div 2=12$ cans of fruit and $60\div 2=30$ cans of vegetables.

7 0

2 years ago