Question

What are the solutions to the equation? p2−12p=13

Answer 1

P² - 12 p - 13 = 0 

Δ = ( -12)² - 4 ( 1 * - 13) 
Δ = 144 + 52
Δ = 196 = 14²

x₁ = (- ( -12) + 14 ) / 2 = 26/2 = 13 
x₂ = ( - ( -12) - 14) /2 = - 2 /2 = - 1 

S = 13

Answer 2

Answer:

The solutions of the given equations are -1 and 13.

Step-by-step explanation:

The given equation is

$p^2-12p=13$

Subtract 13 from both the sides.

$p^2-12p-13=0$

Middle term can be written as -13p+p,

$p^2-13p+p-13=0$

$p(p-13)+1(p-13)=0$

$(p+1)(p-13)=0$

Using zero product property, equal each factor equal to 0.

$p+1=0\Rightarrow p=-1$

$p-13=0\Rightarrow p=13$

Therefore the solutions of the given equations are -1 and 13.