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anastassius [24]
4 years ago
12

Find (12y-1)+(-10y+7)

Mathematics
2 answers:
Pani-rosa [81]4 years ago
8 0

Answer:

2y + 6

Step-by-step explanation:

(12y - 1) + ( - 10y + 7) \\  = 12y - 1  - 10y + 7 \\  = 12y - 10y + 7 - 1 \\  = 2y + 6

tekilochka [14]4 years ago
7 0

Answer:

2y +6

Step-by-step explanation:

(12y-1)+(-10y+7)

Combine like terms

12y -10y  -1 +7

2y +6

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What is the equation of a line that passes through the point (8, −2) and is parallel to the line whose equation is 3x + 4y = 15?
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Step 1

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we have

3x+4y=15

Isolate the variable y

Subtract 3x both sides

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Divide by 4 both sides

y=-\frac{3}{4}x+ \frac{15}{4}

the slope of the given line is

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Step 2

Find the equation of the line that passes through  the point (8,-2) and is parallel to the given line

we know that

if two lines are parallel, then their slopes are equal

The equation of the line into point-slope form is equal to

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we have

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substitute in the equation

y+2=-\frac{3}{4}(x-8)

y=-\frac{3}{4}x+6-2

y=-\frac{3}{4}x+4  or  3x+4y=16

therefore

<u>the answer is</u>

y=-\frac{3}{4}x+4

or

3x+4y=16

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