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ra1l [238]
3 years ago
5

Explain why 3(x+4)=3(x-5) has no solution. Choose the best response below.

Mathematics
2 answers:
ASHA 777 [7]3 years ago
6 0
It's A.

You've got 3 as a coefficient on both sides, so you can divide both sides by 3 to cancel them out. Then you've got:

x + 4 = x - 5

You know that this can't have a solution because there is no value x where if you add 4 to it and subtract 5 from it, you'll get the same thing.

So, the problem with the equation is that the x values have to be the same, but the constant numbers added/subtracted are different.
(If you liked this answer please rate it as brainliest!! thank you!!)
Evgesh-ka [11]3 years ago
3 0
Its either A or C i know that 
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Please help with 2 questions. Thank you.
8_murik_8 [283]

{e}^{ln(anything)}  = anything

so here we have:

{e}^{ln1}  = 1

{e}^{ln5x} = 5x

8 0
3 years ago
look at pic 10 pts will mark brainilest
denpristay [2]
It would be D .........
6 0
3 years ago
What is the range of the values shown on the table? What does the range represent?
hjlf

Answer:

Option D)R: {0 ≤ y ≤ 360}; The range represents the number of miles the car can travel

Step-by-step explanation:

The table in the attached figure

Let

x -----> the amount of gas used in gallons (independent variable)

y ----> the number of miles the car can travel (dependent variable)

In this problem

The domain is the interval -----> [0,12]

0\ gal \leq x \leq 12\ gal

The range is the interval ----> [0,360]

0\ miles \leq y \leq 360\ miles

3 0
3 years ago
Which choice is equivalent to the expression below?
Andre45 [30]

<u>Answer:</u>

C. 4\sqrt{7} -4x\sqrt{7} is correct

<u>Steps</u><u>:</u>

4\sqrt{7} -3\sqrt{7}x-x\sqrt{7} \\\\4\sqrt{7} -3\sqrt{7} x-\sqrt{7} x\\\\4\sqrt{7} +(-3\sqrt{7} x-\sqrt{7} x)\\\\4\sqrt{7} -4\sqrt{7} x

7 0
3 years ago
Read 2 more answers
How many times does the graph of 4x = 32 - x2 cross the x-axis?<br><br> 0<br><br> 1<br><br> 2
Yakvenalex [24]

Answer:

2

Step-by-step explanation:

4x = 32 - x2 would be much clearer if written as 4x = 32 - x^2.  Please use

" ^ " to indicate exponentiation.

Rewrite 4x = 32 - x^2 in the standard form of a quadratic:  x^2 + 4x - 32

Then the coefficients are a = 1, b = 4 and c = -32.

Find the discriminant.  It is b^2-4ac.  

Here, b^2-4ac = 4^2 - 4(1)(-32), or 16 + 128, or 144.

Because the discriminant is positive, we know immediately that this quadratic has two real, unequal roots.

So, the answer to this question is "the graph of 4x = 32 - x^2 cross the x-axis in two places."

4 0
4 years ago
Read 2 more answers
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