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3 years ago

The difference of two integers is thirty. the larger integer is two more than five times the smaller integer. Find the integers

1 answer:

5 0

X=2+5y
x-y=30

basically, all you're doing here is solving a system of equations. use the second equation to find out what x or y means. i'm going to solve it for x.

this is the new equation : x=30+y

now i plug this equation into the first one.

30+y=2+5y

30=2+5y-y
30=2+4y
28=4y
y=7

now that you know what y is, take that second equation we did in the beginning and plug in y.

x-7=30

solve for x

x=37

the two integers are 37 and 7.

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Find the sum of 10 + 5i and its complex conjugate.<br> Write your answer in the form a + bi

gogolik [260]

Answer:

20.

Given, complex number is 10+5i .

We need to find sum of the given complex number and its conjugate. The conjugate of 10+5i is 10-5i. Therefore, the sum will be 10+5i+10−5i=20.

7 0

3 years ago

What is the minimum value of the function y=|x+3|-2 ?

lesya692 [45]

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6 0

3 years ago

If you are reading this please help!!!!

Soloha48 [4]

Given:

$1. -3 x^{2}\left(4 x^{3}-7\right)\\$2. $(6 x-5)(2 x+3)$\\3. $(3 x-1)\left(x^{2}+5 x-2\right)$$

To find:

The product of the polynomials.

Solution:

1. $-3 x^{2}\left(4 x^{3}-7\right)$ $=-3 x^{2}(4 x^{3}) -3 x^{2}(-7)$

Multiply the numerical coefficient and add the powers of x.

$=-12 x^{5}+21 x^{2}$

2. $(6 x-5)(2 x+3)=6 x(2 x+3)-5(2x+3)$

Multiply each term of first polynomial with each term of 2nd polynomial.

Multiply the numerical coefficient and add the powers of x.

$=12 x^2+18x-10 x-15$

$=12 x^2+8x-15$

3. $(3 x-1)\left(x^{2}+5 x-2\right)=3 x(x^{2}+5 x-2)-1(x^{2}+5 x-2)$

Multiply each term of first polynomial with each term of 2nd polynomial.

Multiply the numerical coefficient and add the powers of x.

$=3x^{3}+15 x^2-6x-x^{2}-5 x+2$

Add or subtract like terms together.

$=3x^{3}+14 x^2-11x+2$

The answer for multiplying polynomials:

$1. -12 x^{5}+21 x^{2}$

$2. \ 12 x^2+8x-15$

$3. \ 3x^{3}+14 x^2-11x+2$

3 0

3 years ago

The variables A, B, and C represent polynomials where A=x^2, B=3x+2, and C=x-3. What is AB-C^2 in simplest form?

yuradex [85]

Answer:

AB-C^2 = 3x^3 + x^2 + 9

Step-by-step explanation:

AB = (x^2)*(3x+2)= 3x^3 + 2x^2

C^2= (x-3)^2 = x^2 - 9

AB-C^2 = 3x^3 + 2x^2 - x^2 + 9 = 3x^3 + x^2 + 9

7 0

3 years ago

Read 2 more answers

A rug is shaped like a rectangle whose perimeter is 276276 ftft. the length is 5 times as long as5 times as long as the width. f

ArbitrLikvidat [17]

Width = w

Length = 5w

Given,

Perimeter = 276 ft

5w * w = 276

w² = 55.2

--- w = 7.429670248402684 ≈ 7.43 ft

--- l = 5w = 5*7.43 = <span>37.14835124201342 </span>≈ 37.15 ft

4 0

3 years ago