Ask question

Ask question

All categories

3 years ago

5

3+2/3(3-x)<-7 please help I am stuck

1 answer:

asambeis [7]3 years ago

8 0

Solve the problem then state if it's true or false- this is an order of operation problem. 3+2/3(3-X) this is the problem. Now distribute, 3+ 2/3(3)- 2/3(x)= 3+2- 2/3x so the final expression would be 5-2/3x I don't know about the <-7 part but that's the solution to the first one

You might be interested in

5. Ms. Vallejo is flipping a penny. She flips the coin 15 times and gets head 8 of those times. Based on this information, if Ms

tamaranim1 [39]

Answer:

24

Step-by-step explanation:

60/15=3

3*8=24

7 0

3 years ago

Read 2 more answers

Janae' is buying food for a party. She is buying a cheese tray for $4.50 and a few pounds of fruit for

bogdanovich [222]

Answer:

0.67

Step-by-step explanation:

5 0

3 years ago

A family drives 412 miles in 10 hours? What is their approximate rate of speed in miles per hour?(not 1/10 of an hour just 10 ho

kogti [31]

Answer:

41.2 miles per hour

Step-by-step explanation:

To find the miles per hour you need to find how much they travel each hour. To do this divide 412 by 10. When doing this you get 41.2 miles per hour

3 0

3 years ago

Read 2 more answers

On the graph shown, what is f(-1)?

Naddik [55]

Answer:

where is the graph?

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Mark signed an appointment to receive internet service on his mobile phone for the service he pays a monthly fee plus a charge f

FinnZ [79.3K]

Answer:

<em>Mark used 6.43 megabytes of data.</em>

Step-by-step explanation:

The given equation is: $5.25+0.3m=7.18$ , where $m$ is amount of data used in megabyte.

For finding the amount of data Mark used, <u>we need to solve the above equation for $m$ </u>.

First subtracting 5.25 from both sides, we will get.....

$5.25+0.3m-5.25= 7.18-5.25\\ \\ 0.3m=1.93$

Now, dividing both sides by 0.3 ...........

$m=\frac{1.93}{0.3}=6.4333... \approx 6.43$

<em>(Rounded to the nearest hundredth)</em>

Thus, Mark used 6.43 megabytes of data.

3 0

3 years ago