Let's use a for number of days when he shot 50 shots and b for number of days when he shot 100 shots.
We have:
a + b = 20
We also know that he shot total of 1250 shots:
50a + 100 b = 1250
We have two equations. We can solve them for a and b. Let's rearange first equation for a:
a= 20 - b
We insert this into second equation:
50 * (20 - b ) + 100b = 1250
1000 - 50b + 100b = 1250
50b = 250
b = 5
a = 20 - 5
a = 15
Mark shot 100 shots on 5 days.
The answer is that c3x was the answer
Answer:
answer: black screen is showing for me no question
Answer:
The only multiples of 3 between 20 and 30 are 21, 24, and 27. Only 27 satisfies the condition that it is 3 times the sum of its digits.
Step-by-step explanation:
Answer:
y=4x+7
Step-by-step
(-2,1) and (1,-11)
1)Rule you should use is run over rise aka slope
y²-y^1=
x^2-x^1=
(-11)-1=12
1-(-2)=3
12/3=4
slope =4
2)Rule of point slope intercept
y - y1 = m(x - x1)
y+1=4(x+2)
y+1=4x+8
-1 -1
y=4x+7
