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Serhud [2]
4 years ago
15

PLEASE HELP ME!!!! ILL GIVE YOU POINTS

Mathematics
2 answers:
bezimeni [28]4 years ago
5 0
Well I don’t know for sure but I think it is a broken line graph:)
rjkz [21]4 years ago
5 0

B.) BROKEN LINE GRAPH

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Write the repeating decimal as a fraction.<br>-0.5 =​
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-1/2

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Step-by-step explanation:

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3 years ago
You’re piloting an airplane to prepare for landing you change the planes altitude from a meters to c meters.
soldier1979 [14.2K]

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|a-c| meters

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If I am piloting an airplane to prepare for landing, I change the plane's altitude from a meters to c meters, then the expression that represents the distance between two altitudes is given by |a-c| meters, not by |a+c|.

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Please help ! I have been stuck on this calculus problems, I will mark you brainliest!​
Anna71 [15]

Answer:

\displaystyle J'(3) = -1

General Formulas and Concepts:

<u>Algebra I</u>

  • Functions
  • Function Notation

<u>Calculus</u>

Derivatives

Derivative Notation

Derivative Rule [Chain Rule]:                                                                                       \displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Derivative:                                                                                                                     \displaystyle \frac{d}{dx} [e^u]=e^u \cdot u'

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

<em />\displaystyle J(x) = e^{f(x)}<em />

<em />

<u>Step 2: Differentiate</u>

  1. eˣ Derivative [Derivative Rule - Chain Rule]:                                                  \displaystyle J'(x) = \frac{d}{dx}[e^{f(x)}] \cdot \frac{d}{dx}[f(x)]
  2. Simplify:                                                                                                             \displaystyle J'(x) = f'(x)e^{f(x)}

<u>Step 3: Evaluate</u>

  1. Substitute in <em>x</em> [Derivative]:                                                                              \displaystyle J'(3) = f'(3)e^{f(3)}
  2. Substitute in function values:                                                                          \displaystyle J'(3) = -e^{0}
  3. Simplify:                                                                                                             \displaystyle J'(3) = -1

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e

4 0
3 years ago
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