27y^3 -343 starts out with 27y^3, and 343 is the cube of 7. Thus, we know immediately that 27y3 -343 is the diffeence of two squares.
The appropriate rule is a^3 - b^3 = (a - b)(a^2 + ab + b^2).
Here, we have 27y3 -343 = (3y - 7)(9y^2 + 12y + 49)
Answer:
c
Step-by-step explanation:
you just multiply in the calculator
2x-7/2 = 3-6-5x/6
⇒ 2x+ 5x/6= -3+ 7/2
⇒ 2 5/6x= 1/2
⇒ x= (1/2)/ (2 5/6)
⇒ x= 3/17
The final answer is x= 3/17~
Answer:
(-1)/2
Step-by-step explanation:
Evaluate u + a t where u = 2, a = -5 and t = 1/2:
u + a t = 2 - 5/2
Put 2 - 5/2 over the common denominator 2. 2 - 5/2 = (2×2)/2 - 5/2:
(2×2)/2 - 5/2
2×2 = 4:
4/2 - 5/2
4/2 - 5/2 = (4 - 5)/2:
(4 - 5)/2
4 - 5 = -1:
Answer: (-1)/2
Answer:
a)90 square inches
b)104 cubic inches
Step-by-step explanation:
Dimensions of the bigger box
W= 8 in
H=11 in
D= 3 in
Dimensions of the smaller box
w= 6 in
h= 10 in
h= 2.5 in
therefore, difference in the area of the cupboard
=2[ WH+HD+WD] - 2[wh+hd+wd]
= 2[8*11+11*3+8*3]- 2[6*10+10*2.5+6*2.5]
=290- 200= 90 square inches
volume of the large cupboard = WHD= 8*11*3= 264 cubic in
volume of the small cupboard= whd= 6*10*2.5= 150 cubic in
therefore, 264-150= 114 cubic in more cereal does the large box hold than the small box
