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marissa [1.9K]
3 years ago
5

Crystal owes $8,950 on her Electronics Boutique credit card with a 18.4% interest rate. She owes $6,390 on her Miscellaneous Goo

ds credit cards which has a 22.9% interest rate. What is the total monthly payment needed to pay off both cards in three years, assuming she makes fixed payments and does not charge any more purchases with the card?

Mathematics
1 answer:
Margaret [11]3 years ago
3 0
That is the answer below ⬇️ second pic is how to solve

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Help please with this question?
xxMikexx [17]
G(x+1)= \sqrt{(x+1)^2+4} \\ G(x+1)= \sqrt{x^2+2x+1+4} \\  G(x+1)= \sqrt{x^2+2x+5}
7 0
3 years ago
Help this is really hard
Agata [3.3K]

(2^8 *3^-5* 6^0)^-2 * ((3^-2)/(2^3))^4 * 2^28

anything to the 0 power is 1

(2^8 *3^-5* 1)^-2 * ((3^-2)/(2^3))^4 * 2^28

using the power of power property to take the power inside

(2^(8*-2) *3^(-5* -2) * (3^-2*4)/(2^3*4) * 2^28

simplify

2^ -16 * 3^10 * 3^-8 /2*12   * 2^28

get rid of the division by making the exponent negative

2^-16 * 3^10 * 3^-8 *2*-12   * 2^28

combine exponents with like bases

2^(-16-12+28) * 3^(10-8)

2^(0) *3^2

anything to the 0 power is 1

1*9

9




5 0
3 years ago
Read 2 more answers
One more time!
CaHeK987 [17]
Since q(x) is inside p(x), find the x-value that results in q(x) = 1/4

\frac{1}{4} = 5 - x^2\ \Rightarrow\ x^2 = 5 - \frac{1}{4}\ \Rightarrow\ x^2 = \frac{19}{4}\ \Rightarrow \\
x = \frac{\sqrt{19} }{2}

so we conclude that
q(\frac{\sqrt{19} }{2} ) = 1/4

therefore

p(1/4) = p\left( q\left(\frac{ \sqrt{19} }{2} \right)  \right)

plug x=\sqrt{19}/2 into p( q(x) ) to get answer

p(1/4) = p\left( q\left( \frac{ \sqrt{19} }{2} \right) \right)\ \Rightarrow\ \dfrac{4 - \left(  \frac{\sqrt{19} }{2}\right)^2 }{ \left(  \frac{\sqrt{19} }{2}\right)^3 } \Rightarrow \\ \\ \dfrac{4 - \frac{19}{4} }{ \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{8\left(4 - \frac{19}{4}\right) }{ 8 \cdot \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{32 - 38}{19\sqrt{19}} \Rightarrow \dfrac{-6}{19\sqrt{19}} \cdot \frac{\sqrt{19}}{\sqrt{19}}\Rightarrow

\dfrac{-6\sqrt{19} }{19 \cdot 19} \\ \\ \Rightarrow  -\dfrac{6\sqrt{19} }{361}

p(1/4) = -\dfrac{6\sqrt{19} }{361}
3 0
3 years ago
Nine times the difference of a number and five is the same as 5 increased by nine times the number plus five times the number .
horsena [70]
9(x-5)=5+(9x+5x)
9x-45=5+14x
9x-14x=45+5
-5x=50
X=50/-5
X=-10
8 0
3 years ago
What is the difference between 10 pounds and 10 kilograms
katen-ka-za [31]

Both pound and kilogram are units of measurement of weight or mass. A pound is an imperial unit of mass or weight

7 0
2 years ago
Read 2 more answers
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